- #71
gneill
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shaltera said:Zth=(330.3+j219)
Zl=(330.3-j219)
I=E(1000/1220)(330.3)
Close. Both the Thevenin and Load resistors are still there. You've only accounted for one of them.
If you consider the voltage divider created by the two EQUAL resistors, what must be the potential across the load resistor RL?