Ohm's Law graphing inversed gradient value

So you have I=mV+c.What would m be there?In summary, according to Ohm's Law, when plotting the change in current vs the change in voltage for an ohmic device, the resulting trend line should be linear with a gradient equal to the resistance. However, to find the true resistance value, the gradient value needs to be inversed. This is because the equation for the trend line is y = mx + c, with voltage being plotted as x and current as y. Therefore, the gradient (m) represents the inverse of the resistance.
  • #1
Casius
2
0
Homework Statement
Hey all. This is about Ohm's Law (and specifically resistance). When you plot the change in current vs the change in voltage you should get a linear trend line (providing it is from an ohmic device). The gradient should be the resistance. My questions is why does the gradient value need to be inversed to find the true resistance value?
Relevant Equations
y = mx +c
Hey all. This is about Ohm's Law (and specifically resistance). When you plot the change in current vs the change in voltage you should get a linear trend line (providing it is from an ohmic device). The gradient should be the resistance. My questions is why does the gradient value need to be inversed to find the true resistance value?
 
Physics news on Phys.org
  • #2
Casius said:
Homework Statement:: Hey all. This is about Ohm's Law (and specifically resistance). When you plot the change in current vs the change in voltage you should get a linear trend line (providing it is from an ohmic device). The gradient should be the resistance. My questions is why does the gradient value need to be inversed to find the true resistance value?
Relevant Equations:: y = mx +c
Of voltage and current, which are you plotting as y and which as x?
 
  • #3
haruspex said:
Of voltage and current, which are you plotting as y and which as x?
Voltage x, current y
 
  • #4
Casius said:
Voltage x, current y
So you have I=mV+c.
What would m be there?
 
Back
Top