- #1
MystiqThunder
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Homework Statement
An open organ pipe has a fundamental frequency - corresponding to the first resonant length -of 262 Hz. The room temperature is 20.0°C. What is the length of the pipe. [The answer is 0.66m]
Given: 262 Hz and 20°C
Homework Equations
v = 332 + 0.59t
v = f λ
The Attempt at a Solution
v = 332 + 0.59t
= 332 + 0.59(20°C)
= 343.8 m/s
v = f λ
343.8 m/s = 262 Hz X λ
λ = 1.3122 m
Therefore, the length of the pipe is 1.3 m.
I realize I may be well off. Thanks for your assistance in advance :!)