Oscillator on an inclined plane

In summary: However, there are online resources that can help you with this problem. In summary, if the incline is frictionless and has a coefficient of friction of mus, the displacement from equilibrium is x_0 = -Kx_0 * (1 - muso)^2, where x_0 is the equilibrium position and r is the distance from the equilibrium.
  • #1
Gallium
8
0
A spring with force constant K and negligible mass has one end fixed at the top of an inclined plane making an angle theta with the horizonatal. A mass M is attached to the free end of the spring and pulled down a distance x_0 below the equilibirum position and released. Find the displacement from the equilibrium, position as a function of the time if the incline:
a) is frictionless
b) has a coefficient of friction mu
 
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  • #2
so how I am stuck is that ma + cv + kx = 0 but that the frictional and/or gravitational component will alternatively retard or assist the motion.

Not looking for a handout, but I would like to know the proper eqns to use
 
  • #3
huh? In your equation of motion, you are missing the gravitationnal force (or rather its component in the direction of the plane). The only difference between a) and b) will be that in a) you don't have the frictionnal "cv" term but in b) you do.

These equations are not easy to solve.. I hope you have their solution in your book or notes.
 
  • #4
I don't have BOB (back of book) to consult, if I did then I wouldn't be here posting on an internet physics forum...

any smart people out there?
 
  • #5
The equation ma + cv + kx = 0 is correct. The gravitational force is not needed in the equation since the equilibrium position is the postion the spring is in under normal conditions, i.e. already taking into account the gravitational force.

The only way I can think of to solve the equation is to solve it as a differential equation. Start by letting x = exp(r*t), and differential to find v and a, and substitute into the equation, then solve for r.

If your unfamiliar with differential equations and/or complex numbers, this is probably not the method your expected to use.
 

FAQ: Oscillator on an inclined plane

What is an oscillator on an inclined plane?

An oscillator on an inclined plane is a physical system that consists of a mass attached to a spring, placed on an inclined plane. The system can oscillate due to the force of gravity acting on the mass and the restoring force of the spring.

How does the angle of inclination affect the oscillation of the system?

The angle of inclination affects the amplitude and frequency of the oscillations. A steeper angle will result in a larger amplitude and a higher frequency, while a smaller angle will result in a smaller amplitude and a lower frequency.

What is the equation of motion for an oscillator on an inclined plane?

The equation of motion for an oscillator on an inclined plane is given by:
x(t) = A*cos(ωt + ϕ), where x is the displacement of the mass, A is the amplitude, ω is the angular frequency, and ϕ is the phase angle.

What is the relationship between the period and frequency of an oscillator on an inclined plane?

The period (T) and frequency (f) of an oscillator on an inclined plane are inversely proportional. This means that as the period increases, the frequency decreases and vice versa. The equation for this relationship is: T = 1/f.

What factors affect the period and frequency of an oscillator on an inclined plane?

The period and frequency of an oscillator on an inclined plane are affected by the mass of the object, the spring constant, and the angle of inclination. A larger mass and a steeper angle will result in a longer period and a lower frequency, while a larger spring constant will result in a shorter period and a higher frequency.

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