Peak electric field of a laser light.

Click For Summary
The discussion revolves around calculating the average intensity and peak electric field of a laser beam with a power of 7.0 W and a diameter of 1.0 mm. The average intensity was calculated using the formula P/A, resulting in approximately 8.91 million W/m². However, assistance is needed for determining the peak electric field related to this intensity. The relationship between electric field and intensity is highlighted as a key point for solving part B of the problem. Understanding this relationship is crucial for completing the homework assignment.
Roflcopters
Messages
1
Reaction score
0

Homework Statement




A laser produces an average power of 7.0 W in a light beam 1.0 mm in diameter. Find (a) the average intensity and (b) the peak electric field of the laser light


Homework Equations



Intensity = P/ A
Unsure about part B

The Attempt at a Solution



For part A I did P/( ∏ * r^2) which came to be 7W/( ∏ * .0005^2) which came to 8912676 w/m^2

But I need help finding out how to do part B. Any help would be great.
 
Physics news on Phys.org
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 23 ·
Replies
23
Views
16K
Replies
1
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
9
Views
696
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K