Physic's equation help (Newtons laws)

  • Thread starter Thread starter iluvpandas
  • Start date Start date
  • Tags Tags
    Laws Newtons laws
AI Thread Summary
The discussion revolves around calculating the acceleration of a 35 kg block of cement under a net force of 150 N using Newton's second law of motion. The initial calculation of acceleration was incorrectly stated as a = m/f instead of the correct formula a = f/m, leading to an initial answer of 4.2 m/s². Upon re-evaluation and proper rounding, the correct acceleration was determined to be 4.3 m/s². Participants emphasized the importance of accurate calculations and rounding. The thread highlights common pitfalls in physics homework and the value of peer assistance.
iluvpandas
Messages
7
Reaction score
0

Homework Statement


What is the acceleration of a 35 kg block of cement when pulled sideways with a net force of 150 N?


Homework Equations



what i did was f=ma
a=m/f

and just plugged the numbers in

The Attempt at a Solution



i got 4.2 but when i entered it into the assignment it told me i was wrong.
can someone explain to me where i went wrong?
 
Physics news on Phys.org
iluvpandas said:
what i did was f=ma
a=m/f
You mean, I hope, a = f/m.
i got 4.2 but when i entered it into the assignment it told me i was wrong.
can someone explain to me where i went wrong?
Probably just a round off error. Redo the calculation more accurately, then round off to two digits.
 
i feel so silly
the answer was 4.3
i just needed to round up =P
oh the irony,

thanks so much for helping!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top