Plano-concave thin lens, checking my result

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The discussion revolves around calculating the focal length and power of a plano-concave lens with a given refractive index and radius of curvature. The initial calculation yielded a focal length of 5 cm and a power of -20 diopters, but arithmetic errors were identified in the process. Participants clarified that the correct approach involves recognizing the signs of the radii, leading to a focal length of -20 cm. The final consensus confirms that the focal length is indeed negative, and the power is -5 diopters when calculated correctly. Accurate reporting of units and values is emphasized throughout the discussion.
fluidistic
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Homework Statement


Determine the focal length of a plano-concave lens (n=1.5) which has a radius of curvature of 10 cm. What is its power in diopters?


Homework Equations



None given.

The Attempt at a Solution


1/f=(n-1)(1/R_1-1/R_2)=(1/2)(-0.1)=-1/20.
Thus f=5 cm and P=-20 m^(-1).
Is this right?
 
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Hi,

Your method is mostly correct, but you have made some arithmetic errors.
fluidistic said:

Homework Equations



None given.
Really? Because ...

The Attempt at a Solution


1/f=(n-1)(1/R_1-1/R_2)
... this looks like an equation to me :smile:
=(1/2)(-0.1)=-1/20.
Pretty much correct. R2 is considered negative, so -1/R2 would be +1/(20cm).
(Edit: this is wrong, R2 is positive. See my next post.)
Thus f=5 cm and P=-20 m^(-1).
Is this right?
Not quite. You went from 1/f = 1/20 (←correct) to f = 5 :confused:

Try that last bit of algebra again, you are very close.

RB
 
Last edited:
Redbelly98 said:
Hi,

Your method is mostly correct, but you have made some arithmetic errors.

Really? Because ...... this looks like an equation to me :smile:
I'm not given any tip about what equation to use, therefore I thought I might confuse someone willing to help me if I put a wrong equation in the "relevant equations". But from now on, I must use this section as an attempt to relevant equations. :smile:

Pretty much correct. R2 is considered negative, so -1/R2 would be +1/(20cm).

Not quite. You went from 1/f = 1/20 (←correct) to f = 5 :confused:

Try that last bit of algebra again, you are very close.

RB

From my sketch R_1=infinity and R_2>0. Should I reach 1/f=-1/20?
Ok for the rest, f=20 or -20 depending on my question.
Any ray of light has to pass by the plane part and then the concave part according to my sketch. I'm sure I should reach 1/f=20, but I do not reach this. Should I recheck my calculations? I have (n-1)(-1/R_2) and as R_2>0, I get a negative result. Strange.
Thanks for the help.
 
fluidistic said:
From my sketch R_1=infinity and R_2>0. Should I reach 1/f=-1/20?
You're absolutely correct. For some reason, I read the question as saying "plano-convex". My mistake.

Ok for the rest, f=20 or -20 depending on my question.
It's -20, you were correct about it being negative. Of course, there should be units included when you report the answer.
 
Redbelly98 said:
You're absolutely correct. For some reason, I read the question as saying "plano-convex". My mistake.


It's -20, you were correct about it being negative. Of course, there should be units included when you report the answer.

There's no problem. Thanks for the correction, your time and your help.
As for the units, I think the ones in my first posts are OK.
 
Yes, your first post had correct units but wrong values for f and P.
 
Redbelly98 said:
Yes, your first post had correct units but wrong values for f and P.

I get it, thanks. :smile:
 

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