Pressure in fluids and Archimedes' principle

Click For Summary
The discussion centers on the effects of placing objects in a container of water regarding buoyant force and pressure. When a piece of wood is added, the volume of displaced water remains unchanged, resulting in constant pressure at the bottom of the container. Conversely, adding a metal object increases the volume of displaced water, thereby increasing the pressure at the bottom. The relationship between displaced water volume and water height is emphasized. Overall, the principles of buoyancy and pressure dynamics are affirmed.
MatinSAR
Messages
673
Reaction score
204
Homework Statement
In following picture, a piece of wood and an empty container are floating on a container of water, and a metal object is at the bottom of the container. A) If we take the piece of wood that is on the surface of the water and put it in the container, how will the pressure at the bottom of the water container change? B) If we take that metal object from its place and put it in a container and the container remains floating, how does the pressure at the bottom of the water container change?
Relevant Equations
Archimedes' principle.
1688481668919.png

Hello.
A: If we put this piece of wood in the emty container, the volume of displaced water will not change (because Buoyant Force has not changed), so the pressure at the bottom of the water container doesn't change and it remains constant.
B: If we put the metal in the emty container, the volume of displaced water should increse (because Buoyant Force has increased), so the pressure at the bottom of the water container is increased.
The volume of displaced water is equivalent to change in water's height.

Am I wrong or not?!
 
Physics news on Phys.org
You are correct.
 
kuruman said:
You are correct.
Thanks again for your help.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
Replies
18
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 6 ·
Replies
6
Views
660
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
961
  • · Replies 1 ·
Replies
1
Views
3K
Replies
4
Views
4K