Prove formula for the product of two exponential operators

AI Thread Summary
The discussion revolves around proving the formula Exp(A+B) = Exp(A)Exp(B)Exp(-1/2 [A,B]) for two operators A and B that satisfy specific commutation relations. Participants are advised to define T(s) as Exp(As)Exp(Bs) and differentiate it with respect to s, leading to T'(s) expressed in terms of T(s). There is confusion regarding the application of the Baker-Hausdorff lemma and the proper handling of non-commuting operators. The need for careful manipulation of operator order is emphasized, as switching A and B is not permissible. The overall challenge lies in integrating the derived expression while adhering to the properties of the operators involved.
astrocytosis
Messages
51
Reaction score
2

Homework Statement



Consider two operators A and B, such that [A,[A, B]] = 0 and [B,[A, B]] = 0 . Show that

Exp(A+B) = Exp(A)Exp(B)Exp(-1/2 [A,B])

Hint: define Exp(As)Exp(Bs) as T(s), where s is a real parameter, differentiate T(s) with respect to s, and express the result in terms of T(s). Then use the Baker-Hausdorff lemma, and finally simply integrate your expression.

Homework Equations


[/B]
Baker-Hausdorff Lemma

e-B A eB = A + [B,A] + 1/2! [B,[B,A]] + 1/3! [B,[B,[B,A]]] +...

The Attempt at a Solution



I did what the hint said and took the derivative of T(s)

T'(s) = Exp(A s)Exp(B s) B + Exp(B s)Exp(A s) A

T'(s) = T(s) * (A + B)

but I am very lost as to how to proceed for here. I don't see how the Baker-Hausdorff lemma can be applied to this. I looked online for a derivation of this formula, but they all seemed more complicated than what the problem is asking for, and none of them defined a function like T(s) (that I saw). I think I must be fundamentally misunderstanding something here but I can't figure out what it is. I tried computing T(s) for the case where A, B depend on s, but that just made things more confusing.
 
Physics news on Phys.org
astrocytosis said:

Homework Statement



Consider two operators A and B, such that [A,[A, B]] = 0 and [B,[A, B]] = 0 . Show that

Exp(A+B) = Exp(A)Exp(B)Exp(-1/2 [A,B])

Hint: define Exp(As)Exp(Bs) as T(s), where s is a real parameter, differentiate T(s) with respect to s, and express the result in terms of T(s). Then use the Baker-Hausdorff lemma, and finally simply integrate your expression.

Homework Equations


[/B]
Baker-Hausdorff Lemma

e-B A eB = A + [B,A] + 1/2! [B,[B,A]] + 1/3! [B,[B,[B,A]]] +...

The Attempt at a Solution



I did what the hint said and took the derivative of T(s)

T'(s) = Exp(A s)Exp(B s) B + Exp(B s)Exp(A s) A
You moved the Exp(As) A to the right of Exp(Bs) which is not allowed if A and B don't commute. Be careful to not switch the order of the A and B operators,
 
I thought an analytic function of an operator returned a function of its eigenvalue so it wouldn't matter... but then how can I write it in terms of T(S)?
 
Thread 'Help with Time-Independent Perturbation Theory "Good" States Proof'
(Disclaimer: this is not a HW question. I am self-studying, and this felt like the type of question I've seen in this forum. If there is somewhere better for me to share this doubt, please let me know and I'll transfer it right away.) I am currently reviewing Chapter 7 of Introduction to QM by Griffiths. I have been stuck for an hour or so trying to understand the last paragraph of this proof (pls check the attached file). It claims that we can express Ψ_{γ}(0) as a linear combination of...
Back
Top