- #36
SammyS
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You still haven't correctly stated what is wrong with this.SammyS said:Not quite right.
Details:
##\displaystyle \sqrt {\cos^2\theta + (i^2\sin\theta)}##
is wrong in a couple of ways,
BY the way, the rest of what you had was correct, That is; ##\displaystyle r=\sqrt {\cos^2\theta+\sin^2\theta}=1##
is correct.