Rate of loss of potential energy

In summary, for the given problem, the loss of potential energy for object (b) is calculated to be 175 J, with a rate of 175 W. However, the answer key states the rate to be 80 W, which may be a typo.
  • #1
songoku
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Homework Statement
Please see below
Relevant Equations
PE = mgh
1678204756709.png


I got answer for (a), which is 0.51 m

For (b), loss of potential energy = 35 x 9.81 x 0.51 = 175 J
Rate of loss of potential energy = 175 J / 1 s = 175 W

But the answer key is 80 W. Where is my mistake?

Thanks
 
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  • #2
I think your answer of 175 W is correct.
 
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  • #3
songoku said:
Homework Statement:: Please see below
Relevant Equations:: PE = mgh

But the answer key is 80 W
If one were adhering to the rules of significant figures, your 175 W (175.103048... on my calculator) would round up to 180 W.

Is it possible that the answer key says "180 W" instead of "80 W"?
 
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  • #4
jbriggs444 said:
If one were adhering to the rules of significant figures, your 175 W (175.103048... on my calculator) would round up to 180 W.

Is it possible that the answer key says "180 W" instead of "80 W"?
Maybe it is a typo, the answer is written 80 W.

Thank you very much TSny and jbriggs444
 
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Related to Rate of loss of potential energy

What is the rate of loss of potential energy?

The rate of loss of potential energy refers to how quickly potential energy is being converted into other forms of energy, such as kinetic energy or thermal energy, over time. It is often associated with systems where energy is being transferred due to forces such as gravity or friction.

How is the rate of loss of potential energy calculated?

The rate of loss of potential energy can be calculated using the formula: Power (P) = dU/dt, where dU is the change in potential energy and dt is the change in time. Power is the rate at which energy is being converted and is usually measured in watts (W).

What factors affect the rate of loss of potential energy?

The rate of loss of potential energy is affected by factors such as the mass of the object, the height from which it is falling, the gravitational constant, and any resistive forces like air resistance or friction. For example, a heavier object or a higher drop height will generally result in a greater rate of loss of potential energy due to gravity.

Can the rate of loss of potential energy be constant?

In an idealized system with no resistive forces, such as air resistance or friction, the rate of loss of potential energy can be constant. However, in real-world scenarios, resistive forces usually cause the rate to vary over time. For instance, air resistance increases with velocity, which can alter the rate at which potential energy is lost.

What are some practical examples of the rate of loss of potential energy?

Practical examples include a pendulum losing potential energy as it swings downwards, a roller coaster descending a hill, or water flowing down a waterfall. In each case, the potential energy is converted into kinetic energy and possibly other forms of energy, with the rate of this conversion being the rate of loss of potential energy.

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