Rock thrown off a horizontal cliff

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A stone thrown horizontally from a cliff and a stone dropped from the same height will have the same time of fall due to equal initial heights. However, the displacement of the thrown stone is greater because it travels horizontally while falling. The speed right before impact differs; the thrown stone has a greater resultant velocity due to its horizontal component, which adds to the vertical velocity. This is illustrated by comparing a bullet dropped and one fired horizontally, where the fired bullet impacts with a higher speed. The discussion emphasizes that both stones share the same vertical velocity but differ in horizontal momentum, leading to different overall speeds upon impact.
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The question states a stone is thrown off a cliff horizontal and it eventually hits the ground. A second stone is dropped from rest at the same height and it hits the ground too. The question asks which are the following quantities are the same or different; displacement, speed right before it hits the ground and time. I know that displacement for the first stone is greater because the resultant is greater. The time, I know, is the same but I believe it is because the initial height is the same so it would take the same amount of time. What I don't get is the speed right before it hits the ground. I am guessing it has to do with the component of velocity, vx and vy but I'm not sure why. All I know for sure is for the first stone, the velocity is the same as the vy and there is no vx, and for the second stone the velocity is at an angle right before it hits the ground but why does that necessarily mean, the velocity is greater?
 
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Exaggerate the situation--imagine a bullet dropped from your hand and another bullet fired horizontally from a gun. Which will have the greater speed (magnitude of resultant velocity vector) upon impact?
 
lewando said:
Exaggerate the situation--imagine a bullet dropped from your hand and another bullet fired horizontally from a gun. Which will have the greater speed (magnitude of resultant velocity vector) upon impact?
That makes way more senses.
 
Kiana Hill said:
why does that necessarily mean, the velocity is greater?
Same reason as for displacement: vy is the same for both but vx is different.
 
I'm assuming that this is one of those weightless strings and frictionless planes type of thought experiment. Therefore my first thought was that the vertical component of velocity will be the same as they will both have been falling for the same time prior to hitting the ground, but one has had extra energy imparted to it in the form of momentum therefore the speed that generates must be in addition to the vertical velocity.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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