Skier on a slope (Fnormal, Ffriction, etc)

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In summary, the problem involves a skier being pulled up a slope at a constant velocity by a tow bar. The slope has an inclination of 30.9° and the force applied by the tow bar is parallel to the slope. The skier's mass is 61.4 kg and the coefficient of kinetic friction between the skis and snow is 0.116. To find the magnitude of the force exerted by the tow bar on the skier, the equation Ff=uN is used. By plugging in the given values and solving, the answer is determined to be 59.8925 N.
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Homework Statement



A skier is pulled up a slope at a constant velocity by a tow bar. The slope is inclined at 30.9 ° with respect to the horizontal. The force applied to the skier by the tow bar is parallel to the slope. The skier's mass is 61.4 kg, and the coefficient of kinetic friction between the skis and the snow is 0.116. Find the magnitude of the force that the tow bar exerts on the skier.

Homework Equations



Ff=uN

The Attempt at a Solution



so is it the tow bar force = force of friction? the answer is just u times horizontal component of gravitational force?
 
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or was it u times normal force? 61.4*9.8cos30.9*.116=59.8925 N?
 

FAQ: Skier on a slope (Fnormal, Ffriction, etc)

1. What is the normal force when a skier is on a slope?

The normal force is equal to the component of the skier's weight that is perpendicular to the slope. It acts in the opposite direction of the force of gravity and prevents the skier from sinking into the slope.

2. How does the normal force affect the skier's motion?

The normal force is directly proportional to the skier's acceleration. As the slope increases, the normal force also increases, providing more support and reducing the skier's acceleration. On the other hand, as the slope decreases, the normal force decreases, allowing the skier to accelerate more.

3. What is the relationship between the normal force and the angle of the slope?

The normal force is directly proportional to the cosine of the angle of the slope. This means that as the slope becomes steeper, the normal force decreases, and as the slope becomes more horizontal, the normal force increases.

4. How does friction affect a skier on a slope?

Friction is the force that opposes the skier's motion on the slope. It acts parallel to the surface of the slope and can either help or hinder the skier. If the friction force is greater than the component of the skier's weight parallel to the slope, it will slow down the skier's motion. However, if the friction force is smaller than the component of the skier's weight, it will help the skier maintain their speed.

5. Can the skier's speed be calculated using the normal force and friction force?

Yes, the skier's speed can be calculated using the normal force and friction force, along with other variables such as the slope angle and the skier's mass. By using Newton's second law of motion, the net force on the skier can be calculated, which can then be used to find their acceleration and speed.

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