Sound Intensity: Thresholds of Hearing & Ratio Calculation

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The discussion revolves around calculating the ratio of sound intensities I1 and I2 for two individuals with different thresholds of hearing. Using the reference intensity of 1 × 10-12 W/m2, person 1 has a threshold of -5.00 dB and person 2 has +12.0 dB. The attempted solution used the equation 12 - (-5) = 10 * log(I2/I1) to derive a ratio of I2/I1 as approximately 50.12. However, the user received feedback indicating that the answer was incorrect and seeks clarification on the mistake. The focus is on correctly determining the ratio I1/I2 based on the given thresholds.
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Homework Statement


Using an intensity of 1 × 10-12 W/m2 as a reference, the threshold of hearing for an average young person is 0 dB. Person 1 and person 2, who are not average, have thresholds of hearing that are β1 = -5.00 dB and β2 = +12.0 dB. What is the ratio I1/I2 of the sound intensity I1 when person 1 hears the sound at his own threshold of hearing compared to the sound intensity I2 when person 2 hears the sound at his own threshold of hearing?


Homework Equations


12 - (-5) = 10 * log(I2/I1)


The Attempt at a Solution


17 = 10 * log(I2/I1)
1.7 = log(I2/I1)
I2/I1 = 10^1.7 = 50.12

I submitted this online and it says it is incorrect. Anyone able to see where I went wrong?
 
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I1/I2 is the question.

ehild
 

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