- #36
PAllen
Science Advisor
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Before this thread veers completely into new directions, I thought I would put some numbers and clarifications of the OP experiment. Refer to the picture in the OP.
We have a truck moving fast. At the moment its front passes a light, it flashes. The back of the truck receives the signal at some time and place. A ground observer, B, is standing where the back of the truck passes as it receives the signal. The question was how do they both measure the speed of light to be the same?
We need to add a lot of specificity. Assume some time in the past, we collected identical tape measures and clocks. Now we describe how B and A (a truck traveling scientist) set up to do their measurements.
B) B places a clock where the signal will be received as the back of the truck passes; rolls out tape measure to where the emitter is (carrying a clock) and places clock next to emitter. Assistant stands at this clock to record when the emitter flashes. Scientist walks back to reception point, to await the truck's arrival (where he will record the reception event on his clock).
A) Scientist enters truck with tape measure and two clocks, and waits in back of truck as it gets up to speed. Then leaves one clock at back of truck, carries other to front as he measures the truck. An assistant waits at the front to record emission time according this clock at front of truck. Scientist walks to back of truck to record reception time.
Ok, now for some numbers. All units are light seconds, speed of light is 1 (light second / second), and we imagine we have all the time in the world to walk back and forth many light seconds.
A measures his truck length as 100, the speed of the ground going by as .6 (c). For him, the light took 100 seconds to reach the back and lightspeed is 1.
Now it gets interesting. If everything has been properly set up so that events happen as described at the beginning, then B will measure the distance between emitter and reception point as 50. This is a combination of seeing the truck as length 80, and the fact that the truck will travel 30 between emission and reception. B will measure the time between emission and absorption as 50, getting c for the speed of light. The discrepancy between B's 50 seconds and A's 100 is a combination B seeing A's clock running only 80% as fast as his, but also seeing a large discrepancy between the front and back clocks on the truck. According to B, A's front clock is set 60 seconds ahead of the back clock. So the 100 seconds measured by A is 'really' only 40 of A's seconds. Then since A's clock is only running 80% the rate of B's, this 40 of A's seconds correspond to 50 of B's.
We have a truck moving fast. At the moment its front passes a light, it flashes. The back of the truck receives the signal at some time and place. A ground observer, B, is standing where the back of the truck passes as it receives the signal. The question was how do they both measure the speed of light to be the same?
We need to add a lot of specificity. Assume some time in the past, we collected identical tape measures and clocks. Now we describe how B and A (a truck traveling scientist) set up to do their measurements.
B) B places a clock where the signal will be received as the back of the truck passes; rolls out tape measure to where the emitter is (carrying a clock) and places clock next to emitter. Assistant stands at this clock to record when the emitter flashes. Scientist walks back to reception point, to await the truck's arrival (where he will record the reception event on his clock).
A) Scientist enters truck with tape measure and two clocks, and waits in back of truck as it gets up to speed. Then leaves one clock at back of truck, carries other to front as he measures the truck. An assistant waits at the front to record emission time according this clock at front of truck. Scientist walks to back of truck to record reception time.
Ok, now for some numbers. All units are light seconds, speed of light is 1 (light second / second), and we imagine we have all the time in the world to walk back and forth many light seconds.
A measures his truck length as 100, the speed of the ground going by as .6 (c). For him, the light took 100 seconds to reach the back and lightspeed is 1.
Now it gets interesting. If everything has been properly set up so that events happen as described at the beginning, then B will measure the distance between emitter and reception point as 50. This is a combination of seeing the truck as length 80, and the fact that the truck will travel 30 between emission and reception. B will measure the time between emission and absorption as 50, getting c for the speed of light. The discrepancy between B's 50 seconds and A's 100 is a combination B seeing A's clock running only 80% as fast as his, but also seeing a large discrepancy between the front and back clocks on the truck. According to B, A's front clock is set 60 seconds ahead of the back clock. So the 100 seconds measured by A is 'really' only 40 of A's seconds. Then since A's clock is only running 80% the rate of B's, this 40 of A's seconds correspond to 50 of B's.
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