Spin-Lattice and Spin-Spin Relaxation Time Question

Click For Summary
To determine the spin-spin relaxation time (T2) using the delay time between 90-degree and 180-degree pulses in NMR, the relevant equation is Mxy(t) = Mxy(0) e^(-t/T2). The delay time refers to the interval between these two pulse types, which is crucial for measuring T2. Understanding how to plug in values for Mxy(t), Mxy(0), and t is essential for solving the equation. This discussion emphasizes the need for clarity on these parameters to accurately calculate T2. The relationship between pulse timing and relaxation times is a fundamental aspect of NMR experiments.
Athenian
Messages
143
Reaction score
33
Homework Statement
To find the spin-lattice relaxation time (##T_1##), I could use the below equation to get my value.

$$T_1 = \frac{T_{min}}{\ln{(2)}}$$

For the spin-spin relaxation time, however, is there a similar equation I could use as well to find for ##T_2## (i.e. the spin-spin relaxation time)?
Relevant Equations
The below equation may (or may not) come in handy.

$$M_y = M_0 e^{-t/T_2}$$
$$\ln{(I(t))} = \ln{(I_0)} - \frac{t}{T_2}$$

Note that ##I(t)## is the intensity of the echo.
Please refer to the homework statement.

Or, if one would like to put it in other words, how would I go about finding ##T_2## if I know the delay time between 90-degree and 180-degree pulses? Is there an equation that helps solve this succinctly?
 
Physics news on Phys.org
Athenian said:
Or, if one would like to put it in other words, how would I go about finding ##T_2## if I know the delay time between 90-degree and 180-degree pulses? Is there an equation that helps solve this succinctly?

can you define "delay time between 90-degree and 180-degree pulses" for a person who doesn't know nmr? what experiment does that describe? The question boils down to what values can you plug in for ##M_{xy}(t)##, ##M_{xy}(0)##and ##t##.

The ##T_2## is given using the equation

$$M_{xy}(t) = M_{xy}(0) e^{-t/T_2}$$Link: https://en.wikipedia.org/wiki/Relaxation_(NMR)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 20 ·
Replies
20
Views
2K
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 17 ·
Replies
17
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K