Spring and Gravity Potential Energies

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A 2-kg block dropped from a height of 0.4 m compresses a spring with a constant of 1960 N/m. The energy conservation equation used is mgh = (1/2)kx^2, leading to a calculated compression of 0.089 m. However, there is a discrepancy as the teacher claims the answer is 1.00 m. Participants suggest verifying calculations and discussing the issue with the teacher, noting that the method assumes negligible spring compression. The discussion highlights the importance of accuracy in physics calculations and the potential for errors in teaching.
brendan3eb
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Homework Statement


A 2-kg block is dropped from a height of 0.4 m onto a spring force whose constant k is 1960 N/m. Find the maximum distance the spring will be compressed.


Homework Equations


U1+K1=U2+K2


The Attempt at a Solution


both the initial and final kinetic energy should be 0 so we should get an equation like this:
mgh=(1/2)kx^2+mg(value)

I can't find an expression to put in for value that only has x and no other unknown variables.
 
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The expression you have will work.

Hint: Let the lowest point the block reaches be h=0m.
 
so I would substitute 0 in for value to get x = .089 m, correct? Yeah, that's what I have been getting. However, my teacher told me the answer is 1.00 m. I am starting to wonder if he read off the wrong answer. Do you get .089 m too?
 
I also get .089m. Check to make sure your numbers and units are correct. If they are, then I suggest talking to your teacher about it. Even teachers aren't perfect!:smile:

Technically, the method we are using assumed the spring is compressed a negligible amount, but I think this is a reasonable assumption that wouldn't change the answer that much.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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