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What I mean is a prepared system, which is evolving as a closed system for a while and then you measure some observable of it with a measurement device. The latter part is of course an extension of the closed system by the measurement device.A. Neumaier said:No. An ideal closed quantum system cannot be observed from the outside, hence probabilities do not apply.
We have the interaction of the measured system with the measurement device. This is a quantum system, with the measurment device being macroscopic, which needs some approximate treatment in the sense of quantum-many-body theory. This is all obvious and doesn't touch the apparent problem you want to discuss, i.e., the idea that one has to causally explain the outcome of a single measurement by QT. This is, however, a contradiction in itself, because QT predicts that this outcome is random, except if the system is prepared in a state, where the measured observable takes a determined value (e.g., if it's prepared in an eigenstate of the self-adjoint operator representing the measured observable). Otherwise it's "irreducibly random" and thus the outcome is not determined by the state preparation under consideration.A. Neumaier said:And for observations from the inside of a quantum system, current interpretations - with sole exception of the thermal interpretations - have nothing to say. It would mean for them to give a mathematical definition of what it means for one part of a quantum systems to observe another part!