The Doppler Effect on railroad tracks

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The discussion revolves around a homework problem involving the Doppler Effect as experienced by a machinist on railroad tracks when two fast trains approach from opposite directions. The emitted frequency of the trains' warning signals is perceived at a frequency 50% higher than the original due to the Doppler Effect. The relevant equations for calculating frequency changes when sources and observers are in motion are provided. The participant seeks guidance on how to apply these equations to determine the speed of the trains and the frequency change observed by the machinist. The conversation emphasizes understanding the Doppler Effect in a scenario with moving sources and observers.
mistymoon_38
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Homework Statement



Do not attempt to do this experiment! You are sitting on railroad tracks,
and extremely fast trains are approaching from both the left and the right.
These trains have equal speeds, and both send out a warning signal with their
horns. You hear this signal at a frequency which is 50% higher than the emitted
frequency. Did I say that these trains went fast? How large is the change in
frequency by the signal sent out by one train and observed by the machinist in
the other?

Homework Equations



f+=f0/1-Vs/V (approaching source)
f-=f0/1+Vs/V) (receding source)
f+=(1+V0/V)f0 (observer approaching a source)
f-=1(-V0/V)f0 ( observer receding from a source)

The Attempt at a Solution


I just need a little help getting started, I don't know where to go with this.
 
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In your case, you are observing the sound from a source approaching you. So, use the appropriate formula, and infer what the speed of the trains (the source) must be.

Then you have to use that information to figure out what the Doppler effect amounts to for the case where both observer and source are moving.
 
thanks! i think i got it.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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