- #1
JustinLiang
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Homework Statement
Starting with 2.50 mol of N2 gas (assumed to be ideal) in a cylinder at 1.00 atm and 20C, a chemist first heats the gas at constant volume, adding 1.52x10^4J of heat, then continues heating and allows the gas to expand at constant pressure to twice its original volume. Calculate the final temperature of the gas.
Homework Equations
PV=nRT
ΔU=Q-W
ΔU=nCvΔT
The Attempt at a Solution
The first part suggests that the system is in a constant volume. Thus:
ΔU=Q
nCvΔT=Q
(2.5mol)(5/2)(R)(Tf-20)=1.52x10^4
I solve for Tf and I get 312.5C.
Now the next part suggests the system is at a constant pressure and the volume doubles.
So I use PV=nRT where n, R and P are constant.
V/T=V/T
1/312.5C=2/T
I solve for and I get 625C. However the answer in the back is 899C. What am I doing wrong?
Thanks!