Thermodynamics homework question, , por favor?

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The thermal dynamics problem involves a 2.0 kg quantity of water in a pressure cooker, where the internal energy increases by 8.0 x 10^3 J, but 2.0 x 10^3 J is lost to the surrounding air. The equation used is ΔU = Q - W, with W being zero due to constant volume. The total energy transferred from the range element to the pressure cooker is calculated to be 10.0 x 10^3 J, accounting for both the energy retained and lost. The discussion emphasizes understanding where energy comes from and how it is distributed within the system. The final conclusion confirms that the total heat transferred is indeed 10.0 x 10^3 J.
Shakoa
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Homework Statement

I'm stuck on this thermal dynamics problem. It states: "A 2.0 kg quantity of water is held at constant volume in a puressure cooker and is heated by a range elment. The system's interal energy increases by 8.0 x 10^3 J. However, the pressure cooker is not well insulated, and 2.0 x 10^3 J of energy is transferred to the surrounding air. How much energy is trasferred from te range elment to the pressure cooker as heat?"

Homework Equations



It's an isovolumatic instance, I think, and I'm using ΔU = Q - W, where W = 0 because of the constant volume.
U is internal energy, Q is heat, W is work.

The Attempt at a Solution



I got to this:

ΔU = 8.0 x 10^3 J
W = 0
Q = 8.0 x 10^3 J
However, I don't know where to go from here. The book says that the answer is 1.00 x 10^4. I can't get there. I tried being stupid and doing this: 8.0 x 10^3 - 2.0 x 10^3, but that obviously doesn't work.

I looked at other forums with this question, but Q'=Q makes no sense.
 
Last edited:
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Hello Shakoa,

Welcome to Physics Forums!
Shakoa said:
The book says that the answer is 1.00 x 10^3.
Are you sure the book's answer is 1.00 x 103 J and not 1.00 x 104 J (i.e. 10.0 x 103 J)?
 
Oh, yea, it does. Sorry. Typing error. New keyboard.

I still can't get a "1" in general.
 
Okay, then. :smile:

The water/pressure cooker system increases its energy by 8.0 x 103 J. The air increases its energy by 2.0 x 103 J. What is the total increase in energy? Where is all this energy coming from?
 
:V The heat comes from the heating element? Do I add it? That seems like it would make sense.
 
Shakoa said:
:V The heat comes from the heating element? Do I add it? That seems like it would make sense.
Just map out where the heat (energy) comes from and where it goes.

A total of "x" amount of heat initially goes into the cooker/water sytem; however, the cooker/water system retains only 8.0 x 103 J, while the remaining 2.0 x 103 J is released into the air. So how much is x? :wink:

[Edit: If y apples are put into a basket, and 2 apples fall out of the basket, leaving 8 apples still in the basket at the end, how many apples y were originally put into the basket?]
 
*headdesk* >.< I feel stupid now, and I'll feel stupid if this is wrong... x = 10000/all the heat/1 x 10^4
 
Shakoa said:
*headdesk* >.< I feel stupid now, and I'll feel stupid if this is wrong... x = 10000/all the heat/1 x 10^4
That sounds right to me. :approve: The total heat is 10.0 x 103 J. That was the amount of heat transferred to the pressure cooker (and water system), before some of it was lost to the air. :wink:
 
Very thank you muy merci. :D Thank you bunches! <3
 

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