Three dielectric slabs in a capacitor

[gracy]

http://astarmathsandphysics.com/university-physics/electricity-and-magnetism/parallel-plate-capacitors-html-9fd61e5.gif

Here the two plates have same area "A" ,I want to ask what if they had different areas , will they still form parallel plate capacitors together?

 

[cnh1995]

http://astarmathsandphysics.com/university-physics/electricity-and-magnetism/parallel-plate-capacitors-html-9fd61e5.gif

Here the two plates have same area "A" ,I want to ask what if they had different areas , will they still form parallel plate capacitors together?

Yes. But the capacitance will be different.

 

[gracy]

What will we write in place of A in the below formula ? A or B?
$\frac{Aε0}{d}$ If one plate has area "A" and the other "B"

 

[cnh1995]

The charges have to be uniformly distributed on both the plates and the plates have different areas. I believe the capacitance calculation will be a little complicated.

 

[gracy]

Ok. What will be the formula of capacitance for the plate 2 here

 

[cnh1995]

What are those blue portions? Dielectrics? What are the red lines joining them? Wires?

 

[gracy]

What are those blue portions? Dielectrics? What are the red lines joining them? Wires?

Yes and yes.

 

[cnh1995]

Given the area, separation and permitivitty, its capacitance would be C=Aε/d..

 

[gracy]

A is area of ? And why there isn't "K" present?

 

[cnh1995]

A is area of ? And why there isn't "K" present?

What's the need of k when there is 'ε' which is itself kε_o? A is the area of each plate(which is same throughout). I don't understand why you are analyzing this diagram.

 

[gracy]

Ok. Fine. Let's end this thread here as it is going off topic.