Total work done on clay during Spring Compression

AI Thread Summary
The discussion revolves around calculating the total work done on a 4.63-kg ball of clay during its compression of a spring with a spring constant of 1610 N/m. The maximum compression of the spring was determined to be 0.50230 m. Initially, the user attempted to calculate the work done using the integral of the spring force but arrived at an incorrect value of -203.106 J. After reevaluating, the correct total work done was found to be -180.3 J, calculated using the formula W = Ks + Ub. The user successfully resolved their confusion regarding the calculation.
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Homework Statement



A 4.63-kg ball of clay is thrown downward from a height of 2.69 m with a speed of 5.01 m/s onto a spring with k = 1610 N/m. The clay compresses the spring a certain maximum amount before momentarily stopping.

b) Find the total work done on the clay during the spring's compression.

Homework Equations



Us=integral(-kx dx)

The Attempt at a Solution



From part of the question I found the maximum compression of the spring to be 0.50230 m, and I know that is correct.

I thought that the total amount of work done on something by the spring's compression was equal to the integral that is in the relevant equations section.

Therefore, that is what I did. I Us=integral(-kx dx) from 0 to 0.50230. The resulting answer was -203.106 J. But that is not correct, does anyone have some insight to what went wrong?
 
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Nevermind, i figured it out.

W = Ks + Ub

W=(-1/2)(1610)(0.502302) + (4.63)(9.81)(0.50230)

W= -180.3 J
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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