Trying to Calculate Initial Velocity and Final Velocity

AI Thread Summary
The discussion focuses on calculating initial and final velocities using the equation 1/2 mv^2 = kx^2. The initial velocity was calculated to be approximately 0.7071 m/s, but there are concerns about the accuracy of the spring constant and potential typos in the equation. Participants emphasize the need for more detailed information about the experiment, including the direction of the mass's release and the data collected. Clarifications on the spring's potential energy and compression values are also requested to ensure accurate calculations. Overall, the thread highlights the importance of precise data and clear communication in physics problem-solving.
rosephysics
Messages
1
Reaction score
0
Homework Statement
Ball was released from a spring. I have the ball mass 0.15 kg, spring PE 0.15 J and spring compression 0.05 m. I have to find initial Velocity, initial KE, then initial momentum, final velocity, and final momentum.

I have data plots and I found the slope. (0.3860, 38.05) (0.5883, 38.05) Are the two points on the line.

I tried to calculate initial Velocity but I don't think I used the right formula.

This is all for a homework lab so I can't share the direct file/question. The lab is titled conservation of momentum.
Relevant Equations
I have to find initial Velocity, initial KE, then initial momentum, final velocity, and final momentum.
1/2 mv^2 kx^2
1.2(0.15)v^2 = 1/2 (3)(0.05)^2
0.075 v^2 = 0.00375
V^2 = 0 00375 / 0.075
V^2 = 0.05
Initial Velocity = 0.7071 m/s

I tried to calculate this one. I think for final velocity I should be using the slope? Any help would be appreciated thank you!
 
Physics news on Phys.org
If you cannot share the original file with the question, you need to say more about what you did. "Ball was released from a spring" does not say much to me. You mention that the spring was compressed, OK, but then what? Was the mass shot straight up, straight down or at angle? You mention data plots. What did you measure? What did you plot? Surely you can share the plots.
 
rosephysics said:
spring PE 0.15 J
How do you know?
rosephysics said:
1.2(0.15)v^2 = 1/2 (3)(0.05)^2
(Typo: 1/2 not 1.2)
Spring constant is 3N/m? That doesn’t match your compression and spring PE numbers.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top