Understanding the Infinite Well Potential for Modeling Electron Bound to Atom

swain1
Messages
30
Reaction score
0
I am just trying to get my head round how this models the electron bound to an atom. I don't understand why the potential is zero in the well What physical case corresponds to the condition that V(x)=0 for all values of x?
Thanks
 
Physics news on Phys.org
If V(x) = 0 for all x (as opposed to only inside the well), then you have a completely free particle, with no net force acting on it. Is that what you were after, or did I misunderstand your question?
 
Yes it was, that is what I thought it would be but then I was wondering why the potential could be zero inside the well as this is meant to represent a bound particle.
Also for a completely free particle, would there be a restriction on the value of n? cheers
 
If the electron is in a box with impenetrable walls, then it's equivalent to being in an infinite potential well, in this case with V=0 inside. That is, the problem describes an electron confined to a finite region of space with the only forces acting during collisions with the walls.

Regards,
Reilly Atkinson
 
The infinite square well doesn't really model anything physical. The closest thing that it comes to modeling is a finite quantum well used in semiconductor lasers. However, the square well is basically the simplest test case that you can construct in QM, since it illustrates the quantization of energy levels.
 
What u might be looking for is the schrödinger equation expressed in radius and angle. You can then make a much more accurate picture as you can use the attraction of the electron to the nucleus as the potenital in the from U(x)= -ke^2 /r. This gives a much more accurate picture of an electron round an atom, as the potential isn't infinite or 0, but increases with distance. Hope this helps.
 
I read Hanbury Brown and Twiss's experiment is using one beam but split into two to test their correlation. It said the traditional correlation test were using two beams........ This confused me, sorry. All the correlation tests I learnt such as Stern-Gerlash are using one beam? (Sorry if I am wrong) I was also told traditional interferometers are concerning about amplitude but Hanbury Brown and Twiss were concerning about intensity? Isn't the square of amplitude is the intensity? Please...
I am not sure if this belongs in the biology section, but it appears more of a quantum physics question. Mike Wiest, Associate Professor of Neuroscience at Wellesley College in the US. In 2024 he published the results of an experiment on anaesthesia which purported to point to a role of quantum processes in consciousness; here is a popular exposition: https://neurosciencenews.com/quantum-process-consciousness-27624/ As my expertise in neuroscience doesn't reach up to an ant's ear...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
Back
Top