Velocity of an apple before strikes the surface of a white dwarf.

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An apple dropped from a height of 12.8 million meters above a white dwarf is expected to strike the surface with a specific velocity. The gravitational acceleration of the white dwarf is 3.29 million m/s², but calculations using the formula for constant acceleration yield an incorrect speed of 9.17 million m/s instead of the correct 5.28 million m/s. The discussion highlights the need to account for varying gravitational acceleration as the apple falls, suggesting the use of gravitational formulas that consider distance from the center of mass. Participants emphasize the importance of integrating gravitational effects rather than relying solely on constant acceleration equations. The conversation concludes with the acknowledgment that additional factors may need to be considered for accurate calculations.
ScienceGeek24
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Homework Statement



An apple is dropped from a height of 12.8*10^6 m above the surface of the white dwarf. With what speed does the apple strike the surface of the white dwarf?

M of white dwarf= 1.99*10^30
gravity of white dwarf= 3.29*10^6

Homework Equations



Vf^2=Vi^2+2a(deltaX)

The Attempt at a Solution



I tried doing this v=srqt( 2(3.29*10^6)(12.8*10^6 ) and my result was far of the real answer i got 9.17*10^6 m/s and the answer sheet showed 5.28 *10^6 m/s.

What did I do wrong?
 
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Hi ScienceGeek24 :smile:

(try using the X2 button just above the Reply box :wink:)
ScienceGeek24 said:
I tried doing this v=srqt( 2(3.29*10^6)(12.8*10^6)

that's only for constant acceleration

a white dwarf is only about the size of the Earth, so 107 m is a long way up

you'll need the radius …

isn't there a relation between the radius and mass of a white dwarf? :smile:
 
yes a=Gm/r^2 that's how i got the acceleration of the white dwarf

The radius is equal of the Earth's radius which is 6.37*10^2 and the mass was the same the sun which was 1.99*10^30. However, I still don't understand your question.

 
You'll need to find the gravitational acceleration as a function of distance, and integrate (or use potential energy). :wink:
 
tiny-tim said:
Hi ScienceGeek24 :smile:

(try using the X2 button just above the Reply box :wink:)



ScienceGeek24 said:
yes a=Gm/r^2 that's how i got the acceleration of the white dwarf

The radius is equal of the Earth's radius which is 6.37*10^2 and the mass was the same the sun which was 1.99*10^30. However, I still don't understand your question.

tim's suggestion referred to super-scripts, not the whole post, so your post would look like:
ScienceGeek24 said:
yes a=Gm/r2 that's how i got the acceleration of the white dwarf

The radius is equal of the Earth's radius which is 6.37*102 and the mass was the same the sun which was 1.99*1030. However, I still don't understand your question.
BTW: Earth's radius is significantly greater than 6.37*102m !
 
The thing is that i don't think this problem should be base with integrals, it has to be an easier way, sqrt(3.27*106)(12.8*106+6.37*106) and still i don't get the right answer.

I mean there has to be another factor that I am not taking into account. I know this problem does not need integrals.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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