- #36
Sagittarius A-Star
Science Advisor
- 1,302
- 978
Ad VanderVen said:$$u=\frac{v+w}{1+\frac{vw}{c^{2}}}$$
But which assumption exactly underlies this so that you get exactly this formula and not any other formula with approximately the same properties?
Meir Achuz said:One point to note is that it is circular reasoning to say that the transformation of velocities formula is derived from the Lorentz transformation, because the velocity transformation formula is often a step in the derivation of the Lorentz transformation.
Both, the LT and the relativistic velocity composition can be derived together from the two postulates of SR and assumed linearity. I write a variant of the derivations in "Classical Electromagnetism" by Jerrold Franklin. I think, then the (former revolutionary) transformation formula for time is derived in a more intuitive way. But I like his approach to go via the velocity composition formula to derive the LT.
Definition of the constant velocity ##v##:
##x' = 0 \Rightarrow x-vt=0\ \ \ \ \ \ ##(1)
With assumed linearity follows for the only possible transformation, that meets requirement (1):
##\require{color} x' = \color{red}A(x-vt)\color{black}\ \ \ \ \ \ ##(2)
With SR postulate 1 (the laws of physics are the same in all inertial reference frames) follows, that the inverse transformation must have the same form, if the sign of ##v## is reversed:
##\require{color}x = A(\color{red}x'\color{black}+vt')\ \ \ \ \ \ ##(3)
Eliminating ##x'##, by plugging the right-hand side of equation (2) for ##\require{color} \color{red}x'\color{black}## into (3), and resolving (3) for ##t'## yields the transformation formula for time:
##t' = A(t-x\frac{1-\frac{1}{A^2}}{v})\ \ \ \ \ \ ##(4)
The velocity composition formula follows by calculating ##dx'/dt'## from equations (2) and (4), with ##u=dx/dt##:
##u' = dx'/dt' = \frac{A(dx-vdt)}{A(dt-dx\frac{1-1/A^2}{v})} = \frac{u-v}{1-u(1-1/A^2)/v}\ \ \ \ \ \ ##(5)
With SR postulate 2 (the vacuum speed of light is the same in all inertial reference frames) follows:
##c = \frac{c-v}{1-c(1-1/A^2)/v}\ \ \ \ \ \ ##(6)
##\Rightarrow##
##A= \frac{1}{\sqrt{1-v^2/c^2}} := \gamma\ \ \ \ \ \ ##(7)
Plugging the the right-hand side of (7) for ##A## into (2) and (4) yields the LT.
$$x' = \frac{1}{\sqrt{1-v^2/c^2}} (x-vt)$$
$$t' = \frac{1}{\sqrt{1-v^2/c^2}} (t-vx/c^2)$$
Plugging the the right-hand side of (7) for ##A## into (5) yields the relativistic velocity composition formula.
$$u' = \frac{u-v}{1-uv/c^2}$$
All assumptions are marked in blue.
Last edited: