- #106
Sagittarius A-Star
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Of course, you will not get exactly the GT, except for the special case of ##v=0##, by calculating in case of ##V=1##:Orodruin said:Therefore, letting ##V\to \infty## while keeping ##v## fixed geometrically corresponds to only allowing small rapidities, which would be more accurately referred to as ##v/V \to 0##.
##\lim_{v\to0}\frac{x-vt}{(1-v^2)^{1/2}}=x##
If you are talking about "allowing small rapidities" for an approximately GT, then you must also demand "small enough x-coordinate", to limit the term for "relativity of simultaneity" (##vx/V^2##) in the transformation of time.