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What Causes Superimposition in String Fundamentals and Standing Waves?
- Thread starter lektor
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In the fundamental mode of a vibrating string, the two impulses superimpose to create a standing wave, with the fixed ends determining the wavelength. The fundamental frequency corresponds to the longest wavelength, where the distance between the fixed ends equals the distance between two adjacent nodes, which is half a wavelength. Standing waves also occur in electrical signals, where they propagate through a channel and reflect back, achieving maximum transmission when the forward-to-reflected signal ratio is 1:1. The discussion raises questions about the physical boundaries of acoustic waves and their reflection. Understanding these principles is key to grasping wave behavior in both mechanical and electrical systems.
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Andrew Mason
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The position of the fixed ends of the string determines the wavelength. The fundamental is the longest wavelength of vibration for which the distance between fixed ends is the distance between two adjacent nodes. Any longer wavelength would require the fixed end of the string to move. The distance between two adjacent nodes is 1/2 a wavelength.lektor said:
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Ouabache
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With a string, what is the standing wave, standing between? 
With electrical signals, standing waves occur within a channel (wire, optical fiber etc.). The signal actually propagates the length of the channel and then radiates back. Maximum signal is transmitted when the forward/reflected ratio is 1:1
Thinking about the standing wave graph (time vs amplitude) that lektor gave, does the acoustic wave propagate out to a boundary and reflect back again to its origin? Where would be the physical position of the origin and boundary?
With electrical signals, standing waves occur within a channel (wire, optical fiber etc.). The signal actually propagates the length of the channel and then radiates back. Maximum signal is transmitted when the forward/reflected ratio is 1:1
Thinking about the standing wave graph (time vs amplitude) that lektor gave, does the acoustic wave propagate out to a boundary and reflect back again to its origin? Where would be the physical position of the origin and boundary?
Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance)
My thoughts for the first case , one of them must be 12 volt while the other is 0
The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Here is what I tried
This question was actually asked in one of our engineering entrances.
The answer was 1D.
My teachers say that we have to use μₘ/fₘ to get to this answer. I cannot understand why. I'll be really glad if you could tell me the exact definition of power (numerically) that works in all scenarios.
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