- #1
JustinLevy
- 895
- 1
When working out circuits problems, can we consider a voltmeter to read the difference in the scalar potential between two points
[tex]Voltmeter = V(b) - V(a),[/tex]
or does it tell us a "path potential" / work to move a test charge along a path
[tex]Voltmeter = -\int_a^b \mathbf{E} \cdot d\mathbf{l}[/tex]
?
[tex]Voltmeter = V(b) - V(a),[/tex]
or does it tell us a "path potential" / work to move a test charge along a path
[tex]Voltmeter = -\int_a^b \mathbf{E} \cdot d\mathbf{l}[/tex]
?
Last edited: