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It's in any textbook of quantum theory or quantum field theory. There is an energy-momentum conserving ##\delta##-distribution in the S-matrix.
Together with the probabilistic interpretation of the S-matrix, this gives indeed energy-momentum conservation violations with probability zero. (Thus finitely many exceptions are still allowed, and we can do only finitely many observations.)vanhees71 said:It's in any textbook of quantum theory or quantum field theory. There is an energy-momentum conserving ##\delta##-distribution in the S-matrix.
for which the S-matrix argument does not apply. ##N## photons in does not imply ##N## photons out.A. Neumaier said:the argument by @CoolMint was about particle number conservation,
Gluons, W-bosons, Higgs, etc. are also not conserved but are still considered particles.CoolMint said:Photons are the entities resembling particles the least.
A. Neumaier said:It depends how one counts. Those discussing the unique outcome problem say that there are two outcomes, one at each detector. This is not observed, hence should be explained. The quest for an explanation is the unique outcome problem.
vanhees71 said:But the "unique outcome problem" is solved by Born's probabilistic interpretation of the state. So, where's the problem?
gentzen said:And now you come and ask „where‘s the problem“, the „unique outcome problem“ is solved by Born‘s …
..., this reaction feels very strange to me.
Because the discussion seemed to be about "what is the unique outcome problem" or "why should there be a unique outcome problem," and not about solving it by experimental observations or by postulating specific (reasonable) axioms.vanhees71 said:Why?
I don't think that Schrödinger's "very first" interpretation was the subject of this discussion. Additionally, dots on a photoplate without further context cannot "solve" the problem either. All they do is exhibit a context where the "smeared clouds of continuous charge distributions" interpretation is not applicable. Of course, that naive "smeared" interpretation is almost never a good interpretation, even so smeared charge distributions do occur in the density functional theory.My overall problem with this "strange style" of discussion is that it makes it difficult for me to dive into subtle issues in details. For example, the discussion has now touched topics like "conservation laws event by event" or that "photons are the entities resembling particles the least". As we have seen in discussions with RUTA, boundary conditions can sometimes prevent conservation laws from holding event by event, while still enforcing conservation laws for the quantum expectations.vanhees71 said:Physics is an empirical science, and Schrödinger's interpretation of the physical meaning of his wave function was not in accordance with the observations, i.e., single electrons were not detected as little "smeared clouds of continuous charge distributions" but as dots on a photoplate.
The dots on the photoplate are the empirical facts, and your mathematical framework of the theory supposed to describe these facts together with the "interpretation" of this framework has to be consistent with these observations. Indeed, the distribution of many equally prepared electrons on the photoplate is given by ##|\psi(t,\vec{x})|^2##, the solution of Schrödinger's equation, but the single electron is not detected as a smeared charge distribution but as a dot. This apparent contradiction (known as the "wave-particle dualism" in the old quantum theory) is resolved by Born's interpretation of ##|\psi(t,\vec{x})## as the probability density for the position of the electron, when it is detected at time ##t##. No observations so far contradict this interpretation and it has nobody come up with a satisfactory alternative description. That's why I consider the statistical interpretation of the quantum state a la Born as the solution of the wave-particle-dualism as well as the unique-outcome problem. The unique outcome of measurements, given appropriate measurement devices, are an empirical fact too, and again all there is according to the best currently available theory, QT, are the probabilities for these outcome as predicted by this theory.gentzen said:I don't think that Schrödinger's "very first" interpretation was the subject of this discussion. Additionally, dots on a photoplate without further context cannot "solve" the problem either. All they do is exhibit a context where the "smeared clouds of continuous charge distributions" interpretation is not applicable. Of course, that naive "smeared" interpretation is almost never a good interpretation, even so smeared charge distributions do occur in the density functional theory.
I don't know, what you are referring to here. The conservation laws just say that conserved quantities are conserved. If the system is prepared in an eigenstate of some conserved quantities, then the state at later times stays in such an eigenstate, because the Hamiltonian commutes with the correspond operators representing these conserved quantities. That's a mathematical property of the theory and tells you the event-by-event conservation of conserved quantities. I don't know, which "boundary conditions" you are talking about.gentzen said:My overall problem with this "strange style" of discussion is that it makes it difficult for me to dive into subtle issues in details. For example, the discussion has now touched topics like "conservation laws event by event" or that "photons are the entities resembling particles the least". As we have seen in discussions with RUTA, boundary conditions can sometimes prevent conservation laws from holding event by event, while still enforcing conservation laws for the quantum expectations.
I don't know, what the fundamental axioms of math have to do with this problem. QT is formulated in terms of standard functional analysis.gentzen said:Also with respect to solving the "unique outcome problem" by "postulating specific (reasonable) axioms," there would be interesting subtle details: What sort of postulate would that be? Would it be more of the "2+2=4" type, the "ZFC is consistent" type, or rather the "PA is consistent" type? You see, "2+2=4" is simply true, and "ZFC is consistent" is simply undecidable. But "PA is consistent" is subtle. It is true, it can be proved true in at least three fundamentally different informal ways, but it must be postulated nevertheless.
I've also no clue. Just look at, where (relativistic) QFT is applied to experiments, and you see that the ensemble interpretation perfectly fits. It has a good reason that the LHC and all of its big detectors were upgraded for more luminosity enabling "more statistics"!gentzen said:Maybe more fundamental, I would have found it nice to clarify A. Neumaier's view on Ensembles in quantum field theory. I don't even understand why he thought that you have to "repeatedly prepare a quantum field extending over all of spacetime" in order to use an ensemble interpretation of QFT. But if already the fact that an ensemble interpretation is not universally applicable is never acknowledged, not even in simple examples, then this makes it difficult for me to dive into such subtle issues.
The modern formalism assigns physical meaning to quantities that can be associated to self-adjoint measurement operators. As long as no qualification on the physically relevant measurement operators (spin, energy, momentum, ...) and the physically relevant quantities (probabilities for single outcomes, expectation values, ...) are added, this remains a pure description of a mathematical framework (like ordinay differential equations are the framework for classical point particle physics, partial differential equations are the framework for classical field theories, ...), to which the physical content must still be added.vanhees71 said:Indeed, the distribution of many equally prepared electrons on the photoplate is given by ##|\psi(t,\vec{x})|^2##, the solution of Schrödinger's equation, but the single electron is not detected as a smeared charge distribution but as a dot.
And still this brute force interpretation might miss some subtle details, like I tried to illustrate above.vanhees71 said:No observations so far contradict this interpretation and it has nobody come up with a satisfactory alternative description.
The discussions with RUTA about conservation on average onlyvanhees71 said:I don't know, what you are referring to here.
The easiest way to break a symmetry of the equations of motion is by having physically relevant boundary conditions that are incompatibe with that symmetry, which would have given rise to the conserved quantity. The example from RUTA seem to be easiest explained in terms of such boundary conditions, from my point of view. Of course, symmetries can also be broken for other reasons (at least in classical continuum physics), but those reasons did not apply to his examples, from my point of view.vanhees71 said:I don't know, which "boundary conditions" you are talking about.
They illustrate the subtleties which can still remain despite the agreement that axioms or postulates are indispensible.vanhees71 said:I don't know, what the fundamental axioms of math have to do with this problem. QT is formulated in terms of standard functional analysis.
If you always say "it is simple," or "I don't understand your problem," or "...", then this might be harmless as long as your conversation partner is right anyway and doesn't need your input. But you get him into trouble in the occasional cases where he is wrong, and would have benefitted from you input to see this for himself.vanhees71 said:I've also no clue. Just look at, where (relativistic) QFT is applied to experiments, and you see that the ensemble interpretation perfectly fits. It has a good reason that the LHC and all of its big detectors were upgraded for more luminosity enabling "more statistics"!
This is a claim RUTA makes, but I don't think it is generally accepted.gentzen said:As we have seen in discussions with RUTA, boundary conditions can sometimes prevent conservation laws from holding event by event
I think RUTA wants to make more general claims than that. By "conservation laws holding event by event," I explicitly don't mean the quantum intermediate results, but only the measured classical results. If you measure those classical results in a configuration that they have no chance of both satisfying the quantum expectations, and the conservation laws of the classical results for the specific event, then the quantum expectations will "win".PeterDonis said:This is a claim RUTA makes, but I don't think it is generally accepted.
But the measured classical results are only for the measured system. They don't take into account conserved quantities possessed by the measuring apparatus. This means the measured classical results are useless for evaluating conservation laws, because during the measurement the measured system interacts with the measuring apparatus, so the measured system is not a closed system and you should not expect it to satisfy conservation laws in isolation.gentzen said:By "conservation laws holding event by event," I explicitly don't mean the quantum intermediate results, but only the measured classical results.
Of course the results will match QM predictions, that's been established by countless experiments. But, as above, that's irrelevant to assessing conservation laws.gentzen said:If you measure those classical results in a configuration that they have no chance of both satisfying the quantum expectations, and the conservation laws of the classical results for the specific event, then the quantum expectations will "win".
Agreed. And the measuring apparatus itself is not modeled on the quantum level, it only enters in the form of "boundary conditions" (or some more appropriate word).PeterDonis said:But the measured classical results are only for the measured system. They don't take into account conserved quantities possessed by the measuring apparatus.
Indeed, the idea behind a closed system would be that you don't have to worry about "boundary conditions". But if you perform measurements on the system, then it surely is not a closed system.PeterDonis said:This means the measured classical results are useless for evaluating conservation laws, because during the measurement the measured system interacts with the measuring apparatus, so the measured system is not a closed system
Indeed, I don't expect this. The violation of conservation laws event by event (in such a situation) is much less surprising than the preservation of conservation laws for the quantum expectations.PeterDonis said:and you should not expect it to satisfy conservation laws in isolation.
To be clear, I don't think there is any actual violation of conservation laws--it's just that if you only look at the measured system, you aren't taking into account all the relevant conserved quantities.gentzen said:The violation of conservation laws event by event
PeterDonis said:To be clear, I don't think there is any actual violation of conservation laws--it's just that if you only look at the measured system, you aren't taking into account all the relevant conserved quantities.
I found the huge table again:gentzen said:(Edit: I remember a huge table from "Quantenchemie: Eine Einführung" by Michael Springborg, where many relevant physical interpretations of quantities occurring in quantum chemistry computations were given. If I can find it again, I will include it in another reply.)
##n_R## | ##n_E## | ##n_B## | ##n_\Sigma## | Relevanz für: |
---|---|---|---|---|
0 | 0 | 0 | 0 | Gesamtenergie |
1 | 0 | 0 | 0 | Kräfte; Strukturoptimierung |
0 | 1 | 0 | 0 | Elektrisches Dipolmoment |
0 | 0 | 1 | 0 | Magnetisches Dipolmoment |
0 | 0 | 0 | 1 | Hyperfeinstruktur |
2 | 0 | 0 | 0 | Harmonische Schwingungsfrequenzen und -Moden |
0 | 2 | 0 | 0 | Elektrische Polarizabilität |
0 | 0 | 2 | 0 | Magnetische Polarizabilität |
0 | 0 | 0 | 2 | Kopplung von Spins verschiedener Kerne |
1 | 1 | 0 | 0 | Infrarot Intensitäten |
0 | 1 | 1 | 0 | Circulardichroismus |
3 | 0 | 0 | 0 | Anharmonische Korrekturen zu Schwingungsfrequenzen |
0 | 3 | 0 | 0 | Erste elektrische Hyperpolarisierbarkeit |
1 | 2 | 0 | 0 | Raman Intensitäten |
4 | 0 | 0 | 0 | Anharmonische Korrekturen zu Schwingungsfrequenzen |
0 | 4 | 0 | 0 | Zweite elektrische Hyperpolarisierbarkeit |
(So the table interprets quantities arising in the context of eigenvalue computations. Which makes sense, because those are related to "quasi-equilibrium properties," which are often more relevant than "scattering properties" in chemistry.) The caption of the table then references back to that description in the text:Michael Springborg; Meijuan Zhou: 'Quantum Chemistry' said:14.15 Experimental quantities
Many quantities measured in experiment can also be theoretically determined. In particular, the dependences of the total energy on the structure, the spin of the nuclei, and the components of electric and/or magnetic field vectors are important, i. e., quantities like
$$\frac{\partial E^{n_R+n_E+n_B+n_\Sigma}}{\partial R^{n_R} \partial \mathcal{E}^{n_E}\partial \mathcal{B}^{n_B}\partial \Sigma^{n_\Sigma}}.\qquad(14.91)$$
This notation implies that the experimentally relevant quantities are determined by the ##n_R##-, ##n_E##-, ##n_B##-, and ##n_Σ##-fold derivatives of the total energy ##E## with respect to the nuclear coordinates, the vector components of the electric field, the vector components of the magnetic field, and the components of the nuclear spin.
##n_R## | ##n_E## | ##n_B## | ##n_\Sigma## | Relevance |
---|---|---|---|---|
0 | 0 | 0 | 0 | Total energy |
1 | 0 | 0 | 0 | Forces: structural optimization |
0 | 1 | 0 | 0 | Electric dipole moment |
0 | 0 | 1 | 0 | Magnetic dipole moment |
0 | 0 | 0 | 1 | Hyperfine structure |
2 | 0 | 0 | 0 | Harmonic vibrational frequencies and modes |
0 | 2 | 0 | 0 | Electric polarizability |
0 | 0 | 2 | 0 | Magnetic susceptibility |
0 | 0 | 0 | 2 | Coupling of spins of different nuclei |
1 | 1 | 0 | 0 | Infrared intensities |
0 | 1 | 1 | 0 | Circular dichroism |
3 | 0 | 0 | 0 | Anharmonic corrections to vibrational frequencies |
0 | 3 | 0 | 0 | First electrical hyperpolarizability |
1 | 2 | 0 | 0 | Raman intensities |
4 | 0 | 0 | 0 | Anharmonic corrections to vibrational frequencies |
0 | 4 | 0 | 0 | Second electrical hyperpolarizability |
Unless each of them realizes in another "world".martinbn said:That is still a single outcome.
The issue is not whether the outcome is single, because it clearly is (except in the many world interpretation), but how QM explains single outcomes. The standard QM avoids a need for explanation because it postulates that a single outcome appears when a measurement is performed. However, the measurement itself in standard QM is usually not described in terms of something more elementary. Instead, measurement is taken as a primitive notion that does not need to be precisely defined. It works fine in practice, but it's not satisfying from a deeper point of view where one wants to introduce a wave function of the measuring apparatus. But when one does that, then wave function of the apparatus and of the measured system should a priori be treated on an equal footing, and from this point of view it is not at all obvious what's special about measurement so that single outcomes appear.martinbn said:I don't understand the issue with single outvomes. How can there be anything else? What is a multiple outcome?
That's true when both initial and final value of the conserved quantity is measured. But if the initial state is in the superposition of different values, while final measured state has a definite value, then the initial mean value is not equal to the final definite value.vanhees71 said:No, quantum mechanics implies conservation laws event by event.
In general this is true, but it doesn't mean conservation laws are violated. It just means the system is not a closed system--it interacts with the measuring apparatus during measurement. If a system is not closed, you should not expect it to obey conservation laws in isolation.Demystifier said:if the initial state is in the superposition of different values, while final measured state has a definite value, then the initial mean value is not equal to the final definite value.
You will if you include everything that interacts, which means including the measuring apparatus. As @Demystifier points out, we don't currently have a formulation of QM that does that and also explains (instead of just postulating) single outcomes; that means we don't currently have a formulation of QM that allows us to test conservation laws during measurements.vanhees71 said:event-by-event conservation means that you must have a state
But the full system, namely measured system and measuring apparatus, is closed. And yet, the final definite energy of the full closed system is not equal to its initial mean energy.PeterDonis said:In general this is true, but it doesn't mean conservation laws are violated. It just means the system is not a closed system--it interacts with the measuring apparatus during measurement. If a system is not closed, you should not expect it to obey conservation laws in isolation.
No. it always iteracts with its environment.Demystifier said:But the full system, namely measured system and measuring apparatus, is closed.
Then the full system, namely measured system, apparatus and environment, is closed, and everything I said before applies to this full system.A. Neumaier said:No. it always iteracts with its environment.
Not necessarily; that full system might be in an eigenstate of whatever conserved quantity you are assessing, even if subsystems of it are not.Demystifier said:Then the full system, namely measured system, apparatus and environment, is closed, and everything I said before applies to this full system.
This full system is the whole universe! How do you propose to measure it?Demystifier said:Then the full system, namely measured system, apparatus and environment, is closed
I would say that the full system cannot be in the full Hamiltonian eigenstate. For if it was, the full wave function would have a trivial time dependence proportional to ##e^{-iE_{\rm full}t/\hbar}##, so no decoherence or any other change could happen due to the Schrodinger evolution, which would correspond to a totally dull universe very unlike our own. (BTW such a dull universe is also related to the problem of time in quantum gravity, but that's another issue.)PeterDonis said:Not necessarily; that full system might be in an eigenstate of whatever conserved quantity you are assessing, even if subsystems of it are not.
By neglecting the influence of environment. In real quantum optics experiments, a measured system is often very well isolated from the environment. The apparatus, of course, is not isolated from the environment, but the exchange of energy between apparatus and environment has a negligible influence on the measured system.A. Neumaier said:This full system is the whole universe! How do you propose to measure it?
This is not true.Demystifier said:The apparatus, of course, is not isolated from the environment, but the exchange of energy between apparatus and environment has a negligible influence on the measured system.
No. Since apparatus itself has many degrees of freedom, it is the apparatus that serves as "environment" needed for decoherence of the measured system. The air and other particles around apparatus is not important.A. Neumaier said:The interaction of the apparatus with the environment is the essential ingredient in the derivation of decoherence properties for the measured system + apparatus!!!
I think solving this problem, requires nothing less than understanding the dual perspectives of dynamics as described by a hamiltonian, and the "evolution" describes by agents making measurements on each other. This is exactly the heart of the problem.Demystifier said:but how QM explains single outcomes
...
measurement is taken as a primitive notion that does not need to be precisely defined
...
then wave function of the apparatus and of the measured system should a priori be treated on an equal footing, and from this point of view it is not at all obvious what's special about measurement so that single outcomes appear.
So the evolution of agents is not described by Hamiltonian, right? Do you have some concrete model of agent evolution in mind?Fra said:I think solving this problem, requires nothing less than understanding the dual perspectives of dynamics as described by a hamiltonian, and the "evolution" describes by agents making measurements on each other.
The simple answer would be yes, if by agent we refer to the intrinsic perspective, it's not described by a fixed Hamiltonian simply because a Hamiltonian itself implicitly encodes information that bypassed proper inference. Instead the evolution of the agent from it's own perspective is simply an evolutionary learning process.Demystifier said:So the evolution of agents is not described by Hamiltonian, right? Do you have some concrete model of agent evolution in mind?