- #36
zonde
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I was implying that I doubt whether or not your proposed alternative e.g. nonseparability provide any useful insights into the discussed question.RUTA said:I thought you were talking about coincidence counts at three detectors, so of course you'd need three photons. In any event, if you read that AJP paper, you'll see how to do the math for two photons easy enough. And, you'll see how the experiments are actually carried out, e.g., how coincidence counts involving the |0> state are obtained when |0> means the photon didn't get through the polarizer.
Therefore I proposed to look how you would analyze from your perspective particular experiment.
I would try to explain this experiment another way.
We have three entangle photons with the same polarization that are directed at three different sites (A, B and C).
Lets consider it in two steps. First step:
We make measurements only at two sites (A and B). Relative angle between their PBSes is 45°. So assuming ideal conditions (zero photon count at 90°) measurements from two outputs of their PBSes (say outputs #1) will show correlation 0 or 50% from supposed maximum at 0°.
Second step:
We make measurements at site C too. PBS in site C is rotated so that it makes 22.5° with A and 22.5° with B (right in the middle between A and B). And now we find out two additional correlations - A output#1 vs C output#1 and B output#1 vs C output#1
And these correlations are:
A#1,C#1 - 0.7 or 85% from supposed maximum at 0°
B#1,C#1 - 0.7 or 85% from supposed maximum at 0°
If you like to express it using three photon correlations then it would be like this:
For |A,B,C>:
A#1,C#1 - |1,1,1> + |1,0,1> =probability 0.425 (considering all possible combinations)
B#1,C#1 - |1,1,1> + |0,1,1> =probability 0.425
And correlation from first step is:
B#1,C#1 - |1,1,1> + |1,1,0> =probability 0.25
Is it right from your perspective so far?
Next step
because |1,1,1> + |1,1,0> has probability 0.25 maximum probability for |1,1,1> is 0.25 (|1,1,1> <= 0.25)
because |1,1,1> + |1,0,1> has probability 0.425 minimum probability for |1,0,1> is 0.175
(|1,1,1> + |1,0,1> - |1,1,1> = |1,0,1> >= 0.425 - 0.25 = 0.175)
so we can write inequality |1,1,1> + |0,1,1> + |1,0,1> (+ |0,0,1>) >= 0.425 + 0.175 = 0.6
So we must conclude that there are more photons arriving at output#1 at site C than at output#2. But if we do symmetric calculation for all outputs#2 then we should arrive at exactly opposite conclusion and that is contradiction.
Do you agree with derivation of this inequality and if you agree then where is the problem of this contradiction from your perspective?