What is the angle between the directions of motion of the helium atom

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In the discussion, participants clarify the mechanics of an oblique elastic collision involving an alpha particle and a helium atom. The alpha particle, moving at velocity u, collides with the helium atom, which has negligible velocity, and after the collision, it moves at a 30-degree angle to its initial direction. To find the angle between the helium atom's motion and the alpha particle's initial direction, it's suggested to draw a diagram and resolve the velocity vectors into x and y components, as momentum is conserved in both axes. For the second question regarding the ball's fall, momentum is indeed conserved before it hits the ground, and participants discuss the appropriate equations to use for analysis. Overall, understanding the collision dynamics and momentum conservation principles is crucial for solving these physics problems.
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Homework Statement


Question 1
An alpha particle traveling at velocity u makes an oblique elastic collision with a helium atom moving with a velocity which is negligible compared to u. After the collision the alpha particle moves in the direction inclined at 30 degrees to its initial direction of motion.

What is the angle between the directions of motion of the helium atom and the initial direction of motion of alpha particle?

Question 2
A ball is released from a point a few metres above the ground. By considering the ball Earth system, discuss whether momentum is conserved before the ball reaches the ground.

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I don't really understand the situation in Question 1. For question 2, I do understand that momentum is conserved before the ball reaches the ground. Do I use m1v1=m2v2 or using total KE = total PE...
 
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1. It will help a lot to draw a picture of what's going on. I assume from the question that you have not been able to do this. The alpha particle hits "obliquely", that means not directly in the middle of the helium atom. Consequently the two particles will scatter in two dimensions and not just one. An "elastic" collision is one where kinetic energy is conserved.(click on the link on the word "elastic"). This will allow you to equate kinetic energy before and after the collision.
The problem gives you the direction of the alpha particle, draw that on a piece of paper. Also draw the general direction of the helium atom. You will need to resolve the velocity vectors of each particle into x and y components. Remember, momentum is conserved along the x-axis and also along the y axis.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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