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Homework Statement
A 0.54kg ball falls from rest at a height of 26m and rebounds up 16m. If the contact between the ball and ground lasted 1.8ms, what average force was exerted on the ball?
Homework Equations
F=ma
v²=v0²+2a(x-x0)
v=v0+at
1000ms=1s (1.8ms is 0.0018s)
The Attempt at a Solution
(numbers are shortened for convenience but end results are with actual numbers)
Calculated for velocity:
v²=v0²+2a(x-x0)
v²=0+2(9.8)(26)
v=22.6m/s
Calculated acceleration as ball hits ground:
v=v0+at
0=22.6+a0.0018
a=12,541m/s²
Calculate for force:
F=ma
F=(0.54)(12,541)
F=6772.3N
This is the answer I would try but it is wrong and I am missing something, like the 16m bounce up.
I then tried to subtract the force calculated with the force exerted when the ball bounced back up, which had a force of:
v²=v0²+2a(x-x0)
v²=0+2(9.8)(16)
v=17.7m/s
v=v0+at
0=17.7+a0.0018
a=9838.2m/s²
F=ma
F=(0.54)(9838.2)
F=5312.6N
This is upward force so the resultant for is a downward (6772.3-5312.6)=1459.67N.
This is also wrong and might have some assumptions in it.
What is wrong with the calculations? Is there something that I didn't understand about the questions or the use of the equations?