What is the average force exerted on a 0.54kg ball that falls and rebounds?

In summary, the average force on a 0.54kg ball when it rebounds from a height of 26m and contacts the ground is 6772.3N.
  • #1
312213
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Homework Statement


A 0.54kg ball falls from rest at a height of 26m and rebounds up 16m. If the contact between the ball and ground lasted 1.8ms, what average force was exerted on the ball?


Homework Equations


F=ma
v²=v0²+2a(x-x0)
v=v0+at
1000ms=1s (1.8ms is 0.0018s)

The Attempt at a Solution


(numbers are shortened for convenience but end results are with actual numbers)
Calculated for velocity:
v²=v0²+2a(x-x0)
v²=0+2(9.8)(26)
v=22.6m/s

Calculated acceleration as ball hits ground:
v=v0+at
0=22.6+a0.0018
a=12,541m/s²

Calculate for force:
F=ma
F=(0.54)(12,541)
F=6772.3N

This is the answer I would try but it is wrong and I am missing something, like the 16m bounce up.

I then tried to subtract the force calculated with the force exerted when the ball bounced back up, which had a force of:
v²=v0²+2a(x-x0)
v²=0+2(9.8)(16)
v=17.7m/s

v=v0+at
0=17.7+a0.0018
a=9838.2m/s²

F=ma
F=(0.54)(9838.2)
F=5312.6N

This is upward force so the resultant for is a downward (6772.3-5312.6)=1459.67N.
This is also wrong and might have some assumptions in it.

What is wrong with the calculations? Is there something that I didn't understand about the questions or the use of the equations?
 
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  • #2
Through out the problem acceleration is g.
Your v1 = 22.6 m/s is correct. v2 = 17.7 m/s is correct.
Now the average force is equal to (final momentum - initial momentum)/time of contact.
Note that two momentum have opposite direction.
 
  • #3
v1=22.6
v2=17.7

(final momentum - initial momentum)/time
(v2×m - v1×m)/time
(17.7×0.54 - 22.6×0.54)/0.0018
(9.56 - 12.2)/0.0018
-2.63/0.0018
-1459.67

Is this correct?
 
  • #4
312213 said:
v1=22.6
v2=17.7

(final momentum - initial momentum)/time
(v2×m - v1×m)/time
(17.7×0.54 - 22.6×0.54)/0.0018
(9.56 - 12.2)/0.0018
-2.63/0.0018
-1459.67

Is this correct?
Remember that v1 and v2, and hence their respective momenta, are in opposite directions.
 
  • #5
v1=-22.6
v2=17.7

(final momentum - initial momentum)/time
(v2×m - v1×m)/time
(17.7×0.54 - (-22.6)×0.54)/0.0018
(9.56 - (-12.2))/0.0018
21.76/0.0018
12088.9

Is this right?
 

FAQ: What is the average force exerted on a 0.54kg ball that falls and rebounds?

What is a force?

A force is a push or pull that acts on an object, causing it to accelerate or change its state of motion. Force is a vector quantity, meaning it has both magnitude and direction.

What are Newton's Laws of Motion?

Newton's Laws of Motion are three fundamental laws that describe the behavior of objects in motion. The first law states that an object will remain at rest or in motion with constant velocity unless acted upon by an external force. The second law states that the net force on an object is equal to its mass times its acceleration. The third law states that for every action, there is an equal and opposite reaction.

How does mass affect an object's acceleration?

According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that a larger mass will require a greater force to produce the same acceleration as a smaller mass.

What is the difference between mass and weight?

Mass is a measure of the amount of matter an object contains, whereas weight is a measure of the force of gravity acting on an object. Mass is a constant property and does not change, while weight can vary depending on the strength of gravity. Mass is measured in kilograms (kg), while weight is measured in Newtons (N).

How do forces affect motion?

Forces can cause an object to change its state of motion. An unbalanced force will cause an object to accelerate, while a balanced force will result in no change in motion. Forces can also change the direction of motion, causing an object to accelerate in a different direction.

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