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eatblue
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Homework Statement
The problem
A basketball player 2.00m in height throws the ball at a 40degree angle 10.0m from the basketball post and manages to get the ball through the net without it touching the backboard. If the height of the net is 3.05m from the ground, what is the initial speed of the ball?
Homework Equations
(PE+KE)initial = (PE+KE)final
PE = mgh, KE = (1/2)mv2
W = (Fcosθ)Δx , θ is the angle between the directions F and Δx
The Attempt at a Solution
What I tried:
(PE+KE)initial = (PE+KE)final
set y=0 at the position the ball was thrown
0 + .5vi2 = gh + .5vf2
-> .5vi2 = 9.80m/s2*1.05m + .5vf2
I have no idea how it should be handled from here and this is all the information that was given...
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