What is the Mass of the Uniform Disk Used as a Cam on a Vertical Shaft?

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The discussion centers on calculating the mass of a uniform disk used as a cam on a vertical shaft, with a diameter of 38 cm and a moment of inertia of 7.5*10^-3 kg*m/s. The user applies the parallel axis theorem to derive the mass, concluding with a calculation that yields approximately 0.1385 kg. The relevance of the angular velocity at 70 rpm is questioned but not directly utilized in the mass calculation. The responses affirm that the approach taken is correct, suggesting confidence in the derived mass value. The final mass of the disk is estimated to be closest to 0.14 kg.
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A uniform disk is attached at the rim to a vertical shaft and is used as a cam. The disc has a diameter of 38 cm. The moment of inertia of the disk about the axis of the shaft is 7.5*10^-3 kg*m/s. The shaft rotates uniformly about its axis at 70 rpm. The mass of the disc is closest to:

a.0.12 kg
b. 0.092 kg
c. 0.14 kg
d. 0.18
e.0.16 kg

I don’t know why the angular velocity is given. This is what I managed to do:

Using parallel axis theorem,

I_p = I_cm + M*d^2 = 0.5*M*r^2 + M*r^2 = 1.5*M*r^2

M = (I_p)/(1.5*r^2) = (0.0075 kg*m/s)/(1.5*.19 cm^2) = 0.1385 kg

Thanks.
 
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Is this the right track?

Thanks again.
 
Looks good to me.
 
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