I can't get you. Actually is 11/6 times the VInstinctlol said:So total V is (11/6)q/c ? Can you explain how that is V1?
Capacitors in series are a type of electrical circuit configuration where multiple capacitors are connected one after another, forming a single path for current to flow through. In this configuration, the negative terminal of one capacitor is connected to the positive terminal of the next capacitor, and so on.
To calculate the total capacitance of capacitors in series, you can use the formula: 1/C(total) = 1/C(1) + 1/C(2) + 1/C(3) + ... where C(total) is the total capacitance and C(1), C(2), C(3), etc. are the individual capacitances of each capacitor. This formula shows that the total capacitance is the reciprocal of the sum of the reciprocals of each individual capacitance.
Connecting capacitors in series increases the total capacitance of the circuit. This is because the effective distance between the plates of the capacitors is increased, resulting in a larger area for the electric field to build up. As a result, the total capacitance of the circuit is increased.
No, the total charge stored in capacitors in series is the same as the charge stored in a single capacitor. This is because when capacitors are connected in series, the same amount of charge flows through each capacitor, and the total charge is divided among them.
Capacitors in series are often used to increase the total capacitance in a circuit, which can be useful in various applications such as filtering, energy storage, and smoothing of power supply. They can also be used to divide the voltage in a circuit, as the voltage across each capacitor in series is proportional to its capacitance.