What is the mistake in my series capacitors homework?

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The discussion revolves around a student's confusion regarding the calculation of total voltage in a series capacitor problem. The student initially misapplies the voltage formula, leading to incorrect results. Another participant clarifies that the effective capacitance for capacitors in series is calculated using the reciprocal formula, resulting in an effective capacitance of 6C/11. This effective capacitance can then be substituted back into the voltage equation to derive the correct total voltage. The explanation emphasizes that the total voltage relates directly to the individual voltages across the capacitors when connected in series.
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V = q/c
so v = q/c + q/2c + q/3c
q/c(1+1/2+1/3)
q/c (11/6)
hope this helps
 
So total V is (11/6)q/c ? Can you explain how that is V1?
 
Instinctlol said:
So total V is (11/6)q/c ? Can you explain how that is V1?
I can't get you. Actually is 11/6 times the V
 
Capacitors are connected in series. So the effective capacitance is
1/Cs = 1/C + 1/2C + 1/3C
= 11/6C
Cs = 6C/11
Now substitute this value for C for the equation V = 11/6(Q/C) you ll get Q/C which is nothing but V or V1
Hope you got it now
 

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