What is the significance of the base e in the damped oscillations equation?

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The equation A=Ao(e^-bt/2m) describes the amplitude of damped oscillations, derived from the motion of an oscillator influenced by Hooke's law and a damping force proportional to velocity. The use of base e simplifies mathematical calculations, as its properties make differentiation and integration straightforward. While alternative bases could be used, base e is preferred for its efficiency in solving the equation. The damping constant b and mass m are critical parameters that affect the decay of amplitude over time. Overall, the choice of base e enhances the clarity and usability of the equation in physics.
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My textbook gives the equation A=Ao(e^-bt/2m) for the changing amplitude of damped oscillations. What I don't understand is where this equation comes from. Why make it to the base e? Why not make the equation A=Ao(f^T/t) where f is the factor by which it is decay and T is the period.
 
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Yes, but b is the damping constant and m is the oscillating body of mass m. The formula is the result when you solve the equation of motion of the oscillator. There are two forces, acting on the oscillating body: Hook's force -Dx and a damping force which is proportional to the velocity. So ma=-Dx-bv, where x is the change of length of the spring and a is the acceleration, v is the velocity of the body, D is the spring constant and b is the damping factor. This equation can be solved for x, and it results in a sine function of time, where the amplitude decreases exponentially. You are right, one can use other base for the exponential, but it is simpler in maths to use the base e. ex is a nice function, both its differential quotient and integral is the same as itself.

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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