What is the solution to the equation y''' + 4y'' + 4y'=0?

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To solve the equation y''' + 4y'' + 4y' = 0, the characteristic equation r^3 + 4r^2 + 4r = 0 is derived. This approach treats the third-order ordinary differential equation similarly to a second-order one. The discussion confirms that this method is valid for finding a solution. Participants express agreement on the effectiveness of this technique. The conversation concludes with a shared understanding of the solution process.
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what method do i employ to solve this?

y''' + 4y'' + 4y'=0

does the above lead to something like this?

r^3 +4r^2 +4r=0
 
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Approaching this problem like if it was a 2nd order ODE yield a solution that satisfied the ODE. But I am not sure if this will work all the time.
 
dextercioby said:
Yes,it does.

Daniel.


thx i thought that it did
 

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