What is the speed of sound in air at atmospherical conditions?

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The speed of sound in air can be calculated using the distance and time it takes for an echo to return. In this case, the student claps her hands from 86 meters away and hears the echo after 0.50 seconds. The total distance the sound travels is double the distance to the cliff, resulting in 172 meters. Using the formula V = d/t, the correct calculation gives a speed of 344 m/s, which aligns with the typical speed of sound in air at atmospheric conditions. This confirms the calculation and understanding of the problem.
Sace Ver
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Homework Statement


A student stands 86m from the foot of a cliff, claps her hands, and hears the echo 0.50s later. Calculate speed of sound in air.

Known
•86m
•0.50s

Homework Equations


V=331.4+0.606T

The Attempt at a Solution


V=d/t
V=86m/0.50s
V=172m/s

Is that the first step to the problem? If so I'm not quite sure what the next step is.
 
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Sace Ver said:

Homework Statement


A student stands 86m from the foot of a cliff, claps her hands, and hears the echo 0.50s later. Calculate speed of sound in air.

Known
•86m
•0.50s

Homework Equations


V=331.4+0.606T

The Attempt at a Solution


V=d/t
V=86m/0.50s
V=172m/s

Is that the first step to the problem? If so I'm not quite sure what the next step is.
What is the total distance the sound has to travel between the moment she claps her hand and the moment she hears the echo?
 
Sace Ver said:

The Attempt at a Solution


V=d/t
V=86m/0.50s
V=172m/s

Your formula is correct, but the value of the distance you used isn't.
 
stockzahn said:
Your formula is correct, but the value of the distance you used isn't.
86m x 2 = 172 bc it is an echo?

V=d/t
V=172m/0.50s
V=344m/s
 
That seems to be correct - about 340 m/s is a typical value for the speed of sound of air at atmospherical conditions. I also think that this is the only step of the calculation (at least according to the statement).
 
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