When is the Charge and Electric Energy in a Capacitor Half of Its Final Value?

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In an RC circuit with an 8kOhm resistor and a 3uF capacitor, the final charge on the capacitor is determined by the equation Q(t) = EC(1-e^(t/(RC))). The charge reaches half of its final value at approximately 0.0218 seconds. For the electric energy stored in the capacitor, the relevant equation is not provided, but it is essential to relate energy to charge. The energy in a capacitor is given by U = 0.5 * C * V^2, which can be adapted for time dependence. Understanding these relationships is crucial for solving the problem effectively.
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Homework Statement



part 1. Consider a simple RC circuit consisting of a resistor and a capacitor connected in series to a battery. The resistor has a value of 8kOhms, and the capacitance is 3uF. The final (asymptotic) value of the charge in the capacitor is E*C. At what time is the charge in the capacitor one half of this final value?

part 2. At what time is the electric energy in the capacitor one-half of its final value?

Homework Equations



Q(t) = EC(1-e^(t/(RC)))
E = Voltage
C = Capacitance
t = time

The Attempt at a Solution



for part 1, i set (1-e^(t/(RC))) = .5*EC and got a time of .0218.
for part 2, i don't know the equation to relate electric energy of a capacitor over time. i think that's all i need is just the equation.

thanks in advance!
 
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