Which graph represents the Energy of a photon vs intensity?

AI Thread Summary
Increasing the intensity of monochromatic blue light raises the number of photons but does not affect the energy of each photon. The energy of a photon is determined by the equation E = hƒ, where h is Planck's constant and ƒ is the frequency of light. Therefore, the correct graph should show consistent energy for each photon, aligning with the conclusion that the answer is E. The confusion arises from the answer key indicating C, which contradicts the understanding that photoelectrons are irrelevant to the energy of individual photons. This highlights the importance of distinguishing between photon energy and the effects of light intensity on electron ejection.
YMMMA
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Homework Statement


If X represents the intensity of monochromatic blue light and Y represents the energy of each photon of the light, which one is the correct graph below?

Homework Equations


KE=hƒ-∅, where ∅ is the work function
Energy of a photon= hƒ

The Attempt at a Solution


Increasing the intensity of light does not increase the energy of the photon. However, It does increase the number of photons, which increases the number of ejected electrons (more current). Does that mean the graph is the one with consistent energy in E.
 

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Since "Y represents the energy of each photon of the light," the photoelectrons have nothing to do with the question. The answer is indeed E.
 
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I don’t know why the answer key says it is C, so I had to check on my understanding.
 

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