thanks a million!Chestermiller said:
The radial stress in a rotating thin ring is null because the centrifugal force acting on the particles in the ring is balanced by the internal stress within the ring. This results in a state of equilibrium where the net force on the ring is zero, causing the radial stress to be null.
The axial stress in a rotating thin ring is null because the ring is rotating at a constant angular velocity. This means that the particles in the ring are not accelerating, resulting in no net force acting on the ring in the axial direction. Therefore, the axial stress is null.
The rotation of a thin ring causes the stress distribution to be non-uniform, with the highest stress occurring at the inner and outer edges of the ring. This is due to the centrifugal force acting on the particles, which creates a tensile stress at the outer edge and a compressive stress at the inner edge.
Yes, the radial and axial stress in a rotating thin ring can be non-null if there are external forces acting on the ring, such as friction or external loads. In this case, the net force on the ring will not be zero, resulting in non-null radial and axial stresses.
The thickness of a rotating thin ring does not significantly affect its stress distribution. As long as the ring is thin enough to be considered a membrane, the stress distribution will be the same regardless of its thickness. However, if the ring is thick enough to resist bending, the stress distribution will be different due to the presence of bending stresses.