Why Can't Conservation of Energy Be Used to Solve the Loop Problem in Physics?

AI Thread Summary
The discussion centers on a physics problem involving a child on a frictionless ramp entering a circular loop. The initial attempt to solve the problem using conservation of energy led to an incorrect height calculation of h = 5r/2. The correct approach involves kinematics, yielding a height of h = r/2, which is necessary to ensure the child has enough energy to complete the loop. The confusion arises from equating the speed at the bottom of the ramp with the speed required at the top of the loop. The conversation emphasizes the importance of understanding the dynamics involved rather than solely relying on energy conservation principles.
squirrelschaser
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Homework Statement



Bob starts at rest from the top of a frictionless ramp. At the bottom of the ramp, he enters a frictionless circular loop. The total mass of the child and the cart he sits in his m. What must the height of the ramp be in order for the cart to successfully traverse the loop.

r = radius of loop
h = height of ramp
theta = angle of the ramp (irrelevant though)

Homework Equations

The Attempt at a Solution


[/B]
I solved for the minimum speed at the top of the loop.

Fy = F + mg = mv^2/r

v= sqrt(rg)

I then used conservation of energy.

Initial : mgh
Final : mg2r + (m(sqrt(rg))^2)/2

mgh = mg2r + mrg/2

mgh = 5mgr/2

Cancel stuff out h = 5r/2 (WRONG)

Instead the solution calls for using kinematics not energy conservation.

v= sqrt(rg) stills hold.

vf^2 = vi^2 + 2ax

rg = 0 + 2gsin(theta)*(h/sin(theta)

rg = 2gh

r = 2h

h = r/2 (CORRECT answer)

I understand the mathematical process of the correct solution.
However, I don't understand why I can't use conservation of energy(gives me wrong answer) instead of kinematics.

 

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The second answer (r/2) is clearly wrong since it would not provide enough energy to reach the top of the loop even with no remaining KE.
The calculation goes wrong because it equates the speed at the bottom of the ramp to that required at the top of the loop.
The first answer is correct.
 
The solutions I have showed the second answer as the correct answer.
haruspex said:
The second answer (r/2) is clearly wrong since it would not provide enough energy to reach the top of the loop even with no remaining KE.
The calculation goes wrong because it equates the speed at the bottom of the ramp to that required at the top of the loop.
The first answer is correct.

Really? That's the solution provided to me.
Glad to know I wasn't paranoid or something.

Is there any additional information that would make solving this question using kinematic possible, then?
 
squirrelschaser said:
Is there any additional information that would make solving this question using kinematic possible, then?
The v2-u2=2as equation is effectively KE+PE constant. All that's different is factoring out the mass.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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