- #106
W.RonG
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JesseM said:But this problem is also simple to resolve in the case of continuous space and time, using calculus. Yes, you can divide the trip into an infinite series of smaller and smaller increments, but the time for the arrow to cross each successive increment will be also be getting smaller and smaller, and in calculus it is quite possible to have an infinite decreasing series which sums to a finite number, like 1/2 + 1/4 + 1/8 + 1/16 + ... = 1
If I recall, calculus is based on the assumption that the summation of a very large number of very small increments is for our purposes the equivalent of a continuous function. I'll wait while someone adds up all the above fractions. Oops, there's an infinite number of them so it would take (literally) forever and I don't have that long. In this case we can only have faith that the asymptote actually reaches the final value.
JesseM said:Why couldn't an object move more than one units of space in a single unit of time? After all, for slower-than-light objects, they'd have to move more than one unit of time for each unit of space along their path. ...
I see it as being very difficult to travel two Planck distances in space without first having moved one Planck distance. The only way to achieve more than one Planck distance of movement in one time increment is to traverse all Planck distances simultaneously. Not happening. So I see it as all movement is 1Lp/1Tp, 1Lp/2Tp, 1Lp/3Tp, etc. This implies (since we can't occupy space in an interval smaller or between Lp), that all movement is described by spending a number of Tp's at each location of Lp. Then on to the next Lp location, wait another number of Tp's. etc.
rg
(does this forum have a sig. function? mine is "I thought I was wrong once, but I was mistaken". Oh and smileys.)