Why does my LC circuit not oscillate its energy between Electric & Magnetic fields?

  • #71
I have an idea though, what if I connect my headphones to the AC output of my oscillator? won't the AC be converted to audio?
 
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  • #72
Some of us have been working with radio frequency systems for more than sixty years. We do not need to look at examples on YouTube.

Have you yet heard that quietening when your AM radio is tuned to your oscillator?

James2018 said:
I have an idea though, what if I connect my headphones to the AC output of my oscillator? won't the AC be converted to audio?
NO.
 
  • #73
Baluncore said:
Some of us have been working with radio frequency systems for more than sixty years. We do not need to look at examples on YouTube.

Have you yet heard that quietening when your AM radio is tuned to your oscillator?


NO.
Ok, I have not heard that silence on radio but what if my signal is not strong enough to be picked up by the radio? Maybe I need an amplifier to boost the signal before emitting it. Or if the capacitors have tolerances of 10%? The code 104K on the capacitors means they have a 10% tolerance, their capacitance is not exactly 0.1 uF. So the resonant frequency won't be exactly 612.6 KHz.

" In addition, by varying the amplitude of the broadcast signal for AM radio, the power at which that signal is broadcast is also changed, since amplitude represents the strength of the signal. Thus, instead of picking up low amplitude signals, some radios may pick up no signal at all. FM radio, on the other hand, always remains at a constant amplitude, so the strength of the signal does not change." ( https://illumin.usc.edu/catch-a-wave-radio-waves-and-how-they-work/ )


Also,

"
The third reason AM radio does not sound as good is that AM radio tends to have a lot of interference. There are many natural sources of radio waves, most of which are AM waves, and your radio is unable to differentiate between natural AM waves and those being broadcast by radio stations. Perhaps you have noticed that AM radio tends to sound better at night than during the day. The reason for this is that the sun is a big source of natural AM radio waves.
"
 
  • #74
James2018 said:
So the resonant frequency won't be exactly 612.6 KHz.
612 kHz is at the low frequency end of the AM BC band. Maybe you should reduce the two capacitor values, to move the frequency up near 1 MHz. Tolerance will then not be a problem. If you cannot hear it then, you have a problem with your oscillator.
You will need to sweep across the band to find the oscillator frequency.

If all that fails, you will need an good oscilloscope, or lower the frequency down to a couple of kilohertz where you can hear it without the radio.

What sort of AM radio are you using?

James2018 said:
The third reason AM radio does not sound as good is that AM radio tends to have a lot of interference.
You need that interference, so it will only be quiet when you are tuned to your oscillator. How good AM radio sounds compared to FM is irrelevant.
 
  • #75
Baluncore said:
612 kHz is at the low frequency end of the AM BC band. Maybe you should reduce the two capacitor values, to move the frequency up near 1 MHz. Tolerance will then not be a problem. If you cannot hear it then, you have a problem with your oscillator.
You will need to sweep across the band to find the oscillator frequency.

If all that fails, you will need an good oscilloscope, or lower the frequency down to a couple of kilohertz where you can hear it without the radio.

What sort of AM radio are you using?


You need that interference, so it will only be quiet when you are tuned to your oscillator. How good AM radio sounds compared to FM is irrelevant.
There may be a problem, the multimeter detects an output voltage on the antenna that oscillates in strength and polarity (AC) even if I remove the inductor altogether and open the circuit where the inductor was.
 
  • #76
Do not use a multimeter to measure RF.
Check your battery voltage.

What do you mean by "the antenna"? The oscillator inductor will radiate more than sufficient signal to the AM radio.
 
  • #77
Baluncore said:
Do not use a multimeter to measure RF.
Check your battery voltage.

What do you mean by "the antenna"? The oscillator inductor will radiate more than sufficient signal to the AM radio.
The voltage measured with the multimeter connected in parallel at the wires exactly near the battery, is always fixed and +5.21 volts. The output wire, where the waves are represented as A,B,C,D is where the multimeter measures an output voltage changing in value and sign, in strength and polarity between +1 V and -1 V.
diagram2-png.png
 
  • #78
How does your simulation know that the negative of the battery is the ground reference?

If you are getting ± voltages on the inductor, then I guess you must be using a DC range on the meter to measure the AC.
You may not be aware that the inductor is floating, without DC bias, since every DC bias path is blocked by a capacitor. That might explain partly why your meter is confused.

Measure the DC voltage of the emitter and collector of Q1 to ground. That should identify if the transistor might be oscillating.
 
  • #79
Baluncore said:
How does your simulation know that the negative of the battery is the ground reference?

If you are getting ± voltages on the inductor, then I guess you must be using a DC range on the meter to measure the AC.
You may not be aware that the inductor is floating, without DC bias, since every DC bias path is blocked by a capacitor. That might explain partly why your meter is confused.

Measure the DC voltage of the emitter and collector of Q1 to ground. That should identify if the transistor might be oscillating.
Yes, every path from the battery to the antenna is blocked by a capacitor connected in series. DC voltage cannot pass through a capacitor connected in series. Why I think that? Because DC charges the capacitor then the capacitor stays charged and acts like an open circuit.

Only AC voltage can pass through a capacitor because it regularly charges and discharges the capacitor. The base of the transistor is connected in series to the capacitor C1, the collector to the capacitor C4 and the emitter to C3.

Am I wrong? Can DC voltage pass through a capacitor connected in series?
 
  • #80
Ok, here is the AC output interpreted by the sound card of my computer as "Line In" signal through a Jack connector. It is a buzzing sound, just like on the radio receiver. Like a bee.
Spectrum:
osc.png

Waveform:

imagine_2024-09-29_053150564.png
 
  • #81
James2018 said:
Yes, every path from the battery to the antenna is blocked by a capacitor connected in series. DC voltage cannot pass through a capacitor connected in series. Why I think that?
It does not matter why you think that, but you can throw out one of those two coupling capacitors, either the one on the collector or the base. The two tuning caps must stay, with the same ratio. I would throw out the collector coupling capacitor, C4.

James2018 said:
Ok, here is the AC output interpreted by the sound card of my computer as "Line In" signal through a Jack connector. It is a buzzing sound, just like on the radio receiver. Like a bee.
You need to turn off the computer and stop plotting meaningless spectra. Those fascinating distractions, will only confuse you.

You must listen with your ear, for quietening of the AM audio, when tuned to the oscillator. That quieting should be replaced by noise when the oscillator is turned off.

I ask again; what sort of AM radio are you using?
 
  • #82
Baluncore said:
It does not matter why you think that, but you can throw out one of those two coupling capacitors, either the one on the collector or the base. The two tuning caps must stay, with the same ratio. I would throw out the collector coupling capacitor, C4.


You need to turn off the computer and stop plotting meaningless spectra. Those fascinating distractions, will only confuse you.

You must listen with your ear, for quietening of the AM audio, when tuned to the oscillator. That quieting should be replaced by noise when the oscillator is turned off.

I ask again; what sort of AM radio are you using?
This sort of AM radio. But what IF I am using the wrong resistor values in the circuit, too low resistance, 56 ohms, 13 ohms, what if I need to use a lot higher? I thought a lot higher resistance would stop current from flowing at all.

radio-portabil-selecline-841641-8820873560094.png
 
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  • #83
James2018 said:
But what IF I am using the wrong resistor values in the circuit, too low resistance, 56 ohms, 13 ohms, what if I need to use a lot higher?
So, are you saying the diagrams you have supplied do not match what you have built?!!

That is sort of like putting a bicycle tire on a car and wondering why it always looks flat.
 
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  • #84
While the oscillator will not work if the DC bias is too far out, resistor values are a red-herring. Your oscillator will produce sufficient signal for the AM radio, when you sit them next to each other. You just need to turn the computer off, and make an oscillator that operates in the MW band.
 
  • #85
The component values you have used are a bit of a mystery.
It is important that you list the values you have actually used, before progressing.

The inductor value is critical. What is the value ?
The inductor you show in the photo, in post #47, just does not look sufficient for the bottom of the MW band.
 
  • #86
Baluncore said:
The component values you have used are a bit of a mystery.
It is important that you list the values you have actually used, before progressing.

The inductor value is critical. What is the value ?
The inductor you show in the photo, in post #47, just does not look sufficient for the bottom of the MW band.
Finally I have received on the AM radio, a sound beep composed of three sound frequency spikes: 1000 Hz, 2000 Hz and 3000 Hz. 1000 Hz was the loudest, 24 decibels louder than the rest of the spectrum. I have moved the circuit away from other devices to hear the beep on the AM radio, then a minute later I recorded the beep. Although the AM radio frequency was more driven towards 700 KHz (somewhere in the middle between 600 and 700) rather than 612 KHz. I guess that would be the 10% tolerance of the capacitors.
 
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  • #87
Baluncore said:
The component values you have used are a bit of a mystery.
It is important that you list the values you have actually used, before progressing.

The inductor value is critical. What is the value ?
The inductor you show in the photo, in post #47, just does not look sufficient for the bottom of the MW band.
The value is 1.35 uH but I cannot show it because it is covered in a yellow insulator tape. It has 37 turns, 0.4 cm radius and 6,4 cm length. I calculated it here: https://www.allaboutcircuits.com/tools/coil-inductance-calculator/

The capacitors have the code 104K which means 0,1 uF with tolerance 10% except for C3 which has 1 uF. All resistors have 56 ohms with exception for resistor R3 which has 33 ohms.
 
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  • #88
James2018 said:
Finally I have received on the AM radio, a sound beep composed of three sound frequency spikes: 1000 Hz, 2000 Hz and 3000 Hz. I have moved the circuit away from other devices to hear the beep, then a minute later I recorded the beep. Although the AM radio frequency was more driven towards 700 KHz rather than 612 KHz. I guess that would be the 10% tolerance of the capacitors.
Any beeps or buzzes etc you hear IS NOT your oscillator.... its coming
from something else On your work bench.... probably the computer.
Which Baluncore has also told you to turn off.
Baluncore has told you multiple times that you need to tune the radio
carefully to find the quiet spot = the oscillator. If you don't find that spot then your oscillator isn't working OR it is on some far away frequency.
You need an oscilloscope else you will not figure out what is happening with your circuit.
You also need to start listening carefully to what people are trying to teach you and answer their questions instead of responding with random comments :smile:

Cheers
Dave
 
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  • #89
davenn said:
Any beeps or buzzes etc you hear IS NOT your oscillator.... its coming
from something else On your work bench.... probably the computer.
Which Baluncore has also told you to turn off.
Baluncore has told you multiple times that you need to tune the radio
carefully to find the quiet spot = the oscillator. If you don't find that spot then your oscillator isn't working OR it is on some far away frequency.
You need an oscilloscope else you will not figure out what is happening with your circuit.
You also need to start listening carefully to what people are trying to teach you and answer their questions instead of responding with random comments :smile:

Cheers
Dave
Yes, but I cannot find the quiet spot anywhere between 530 KHz and 1700 KHz. I did follow the online scheme for the Collpits oscillator except I used lower resistances. If it did work for the one who invented the scheme, why wouldn't it work for me?
 
  • #90
James2018 said:
Yes, but I cannot find the quiet spot anywhere between 530 KHz and 1700 KHz.

Then, as I said, either the oscillator isn't working, or if it is working, its frequency is outside of that range.
You need an oscilloscope to determine what your circuit is doing
 
  • #91
View attachment 351647
If that spectrum is realistic, I suspect that those low resistor values have made the circuit into an RC oscillator.

I recommend that you put the correct resistors (as shown in the simulation) in the circuit; you might actually get the expected results. (The batteries will last longer too.)

Just for grins, change the resistor values in the simulation to the values you actually used. It would be interesting to see what results you get.

Cheers,
Tom
 

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  • #92
Tom.G said:
View attachment 351647
If that spectrum is realistic, I suspect that those low resistor values have made the circuit into an RC oscillator.

I recommend that you put the correct resistors (as shown in the simulation) in the circuit; you might actually get the expected results. (The batteries will last longer too.)

Just for grins, change the resistor values in the simulation to the values you actually used. It would be interesting to see what results you get.

Cheers,
Tom
Yes, that is what I am going to do, I am going to make a simulation of the actual circuit and see what it does.
 
  • #93
Oops, seems resonant frequency of my circuit is actually 40 Hertz. In this simulation I used every value for resistor, capacitance and inductance and input DC voltage like in real circuit.
imagine_2024-09-29_101328107.png


Here is the animation to see AC is present in the tank circuit
ezgif-1-69cc1dc480.gif
 
  • #94
Antenna oscilloscope - not a pure sine wave, but beats
imagine_2024-09-29_105312339.png
 
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  • #95
The Colpitts circuit you are using has bias voltage dependent on the Re and Rc values.
Here is a different Colpitts circuit, one that I prefer, it uses fewer components and the bias is not dependent on the exact resistance values. Design is for 1 MHz. It has no antenna, the RF output is from the coil current of ±2.7 mA peak, while the circuit runs on less than 0.5 mA.

1MHz-Colpitts.png
 
  • #96
Baluncore said:
The Colpitts circuit you are using has bias voltage dependent on the Re and Rc values.
Here is a different Colpitts circuit, one that I prefer, it uses fewer components and the bias is not dependent on the exact resistance values. Design is for 1 MHz. It has no antenna, the RF output is from the coil current of ±2.7 mA peak, while the circuit runs on less than 1 mA.

View attachment 351662
And it doesn't matter what resistance values I use, at all? And what values are for capacitance for C1, C2, C3? I don't understand the codes.
 
  • #97
James2018 said:
C1, C2, C3? I don't understand the codes.
The convention on circuit diagrams is to move the SI prefix to where the decimal point was. That prevents problems with missing decimal points.
C1 = 0u1 = 0.1 uF = 100 nF.
C2 = 1n0 = 1.0 nF.
C3 = 220p = 220 pF = 0n22.

Keep R1 = R2, at about 33k. Anything from 22k to 47k is OK.
Make R3 about half of R1. 12k to 22k should be OK.
 
  • #98
Baluncore said:
The convention on circuit diagrams is to move the SI prefix to where the decimal point was. That prevents problems with missing decimal points.
C1 = 0u1 = 0.1 uF = 100 nF.
C2 = 1n0 = 1.0 nF.
C3 = 220p = 220 pF = 0n22.

Keep R1 = R2, at about 33k. Anything from 22k to 47k is OK.
Make R3 about half of R1. 12k to 22k should be OK.
But my battery cannot deliver currents through resistors with values above 1k. It is not alkaline. I will try but I have to order online these high resistance values they are not found in the local electronics shop. But wait I can make them out of graphite and paper. https://pxt.azureedge.net/blob/fe8d...tutorial/make-a-resistor/clip-to-resistor.jpg
 
  • #99
James2018 said:
But my battery cannot deliver currents through resistors with values above 1k. It is not alkaline. I will try but I have to order online these high resistance values they are not found in the local electronics shop.
Rubbish .... what sort of battery ?
 
  • #100
James2018 said:
But my battery cannot deliver currents through resistors with values above 1k. It is not alkaline
Your battery is 5 volts, is it not?
Ohms law applies. It is low value resistors you must avoid.
Your battery may have trouble supplying the current of 45 mA needed for your 56 ohm base bias circuit.
 
  • #101
davenn said:
Rubbish .... what sort of battery ?
Coin battery... It drains quickly and delivers 15mAh
 
  • #102
Baluncore said:
Your battery is 5 volts, is it not?
Ohms law applies. It is low value resistors you must avoid.
Your battery may have trouble supplying the current of 45 mA needed for your 56 ohm base bias circuit.
I will make those high value resistors with graphite and paper. I cannot find them for sale so easily in my country
 
  • #103
James2018 said:
I will make those high value resistors with graphite and paper. I cannot find them for sale so easily in my country
Which country ?
 

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