- #36
Twinfun2
- 32
- 0
negitron said:Yes, just leave the chip out (but all the ancillary components in place) and check the voltages at the points where the pins of the chip would be. No, the circuit won't function under these conditions, but you will still have some voltages, either directly from +Vs or through a resistor.
Good deal; makes sense now. I'll post right after I get the ratings.