Why Is My Kinetic Energy Calculation Incorrect?

Click For Summary
The student calculates the kinetic energy of a 0.22 kg rock thrown horizontally at 20.0 m/s using the formula Ek = mv^2/2, arriving at an answer of 9.68 J. However, the expected answer is 44 J, leading to confusion about the calculation's accuracy. The issue likely stems from incorrect arithmetic or order of operations when inputting numbers into the calculator. It's emphasized that the calculation should be straightforward and may not even require a calculator. The discussion highlights the importance of careful calculation to avoid errors in physics problems.
DPXJube
Messages
12
Reaction score
0

Homework Statement


A student throws 0.22kg rock horizontally at 20.0m/s from 10.0m above the ground. Ignore air resistance.

Find the initial kinetic energy of the rock


Homework Equations


Ek = mv^2/2


The Attempt at a Solution


This sounds INCREDIBLY easy and every shape or form
Simplying plugging in what I know

Ek =(0.22)(20.0)^2/2

Get's me the answer of 9.68
However APPARENTLY that's the wrong answer
The answer that I'm given is 44J
How is this possible? I must have gone completely off track somewhere.
 
Physics news on Phys.org
Check your arithmetic. Pay careful attention to the order of operations.
 
DPXJube said:

Homework Statement


A student throws 0.22kg rock horizontally at 20.0m/s from 10.0m above the ground. Ignore air resistance.

Find the initial kinetic energy of the rock

Homework Equations


Ek = mv^2/2

The Attempt at a Solution


This sounds INCREDIBLY easy and every shape or form
Simplying plugging in what I know

Ek =(0.22)(20.0)^2/2

Get's me the answer of 9.68
However APPARENTLY that's the wrong answer
The answer that I'm given is 44J
How is this possible? I must have gone completely off track somewhere.

Your (red) statement is correct - if clumsily written - it would appear the only problem is when you start entering the numbers into your calculator - not that you should need one for that calculation.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 39 ·
2
Replies
39
Views
4K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
1
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K