A force F is exerted on the top right corner of a rectangular plate at

In summary, the magnitude of the torque of a force F exerted on the top right corner of a rectangular plate at an angle of 60 degrees above the horizontal about point A, the lower left corner, is given by the sum of the torques produced by the x and y components of the force, which is either y*F*cos(60) - x*F*sin(60) or x*F*sin(60) - y*F*cos(60). The correct answer will depend on the specific values of x and y.
  • #1
cmkc109
103
0

Homework Statement



A force F is exerted on the top right corner of a rectangular plate at an angle 60o
above the horizontal, as shown below. The magnitude of the torque of the force F
about point A, the lower left corner is given by

See picture please : http://tinypic.com/view.php?pic=2njv9xt&s=6


Homework Equations



Both y and x are being pulled upwards, so that is counterclockwise..
but answer is Fx sin 60 + Fy cos 60
I don't understand torque at all.. can someone please help.


The Attempt at a Solution



No idea..
 
Physics news on Phys.org
  • #2
Hint:
 

Attachments

  • Torque.png
    Torque.png
    2.7 KB · Views: 1,344
  • #3
Thank you!
but I'm still kinda lost...
 
Last edited:
  • #4
one question, where do i put the angle in?
 
  • #5
I'll do a new drawing as I don't think my first was very helpful. Back soon.
 
  • #6
ok thanks, check ur msg too please , thanks
 
  • #7
Try this drawing. The idea is to split the force F into two component forces. Then multiply each component force by it's distance from the pivot to give two torques (Torque = force * distance). Finally you simply add the two torques.
 

Attachments

  • Torque.png
    Torque.png
    26.7 KB · Views: 1,262
  • #8
this is the drawing i had, but from this picture, it shows that it is Fy sin 60 and Fx cos 60 , but the answer is opposite.
 
  • #9
Seems ok to me.

The two components are

F*Cos(60)
F*Sin(60)

Multiply by their distance from the pivot..

y*F*Cos(60)
x*F*Sin(60)

then add.

x*F*Sin(60) + y*F*Cos(60)

Thats' the answer you gave in your first post.
 
  • #10
it still seems to be Fx cos 60 + Fy sin 60 to me :/
 
  • #11
cmkc109 said:
it still seems to be Fx cos 60 + Fy sin 60 to me :/
You need to multiply the x by the component of F that's perpendicular to it, so that's the Y component, F sin(60o).
However, none of the offered answers is correct. The X and Y components of F act in opposite sense around A, so there should be a minus sign somewhere. E.g. consider the case where y = x tan(60o). There should be no moment.
 
  • #12
The X and Y components of F act in opposite sense around A, so there should be a minus sign somewhere.

Oops I missed that.

So answer should be either...

x*F*Sin(60) - y*F*Cos(60)

or

y*F*Cos(60) - x*F*Sin(60)
 

Attachments

  • Torque.jpg
    Torque.jpg
    12.5 KB · Views: 860
Last edited:
  • #13
Thank you! makes sense now
 

FAQ: A force F is exerted on the top right corner of a rectangular plate at

What is the effect of the force on the rectangular plate?

The force exerted on the top right corner of a rectangular plate will cause the plate to move in the direction of the force. This movement may be in the form of translation or rotation, depending on the shape and size of the plate.

How does the magnitude of the force affect the plate?

The magnitude of the force will determine the amount of acceleration the plate experiences. A larger force will result in a greater acceleration, while a smaller force will result in a smaller acceleration.

Will the rectangular plate deform under the force?

The deformation of the plate will depend on its material properties and the magnitude and distribution of the force. If the force is within the elastic limit of the plate's material, it will likely return to its original shape once the force is removed. However, if the force exceeds the elastic limit, the plate may permanently deform.

How does the angle of the force affect the plate?

The angle of the force relative to the plate will determine the direction and magnitude of the resulting movement. If the force is applied perpendicular to the plate, it will result in translation. However, if the force is applied at an angle, it may result in both translation and rotation.

How can the force be calculated or measured?

The force can be calculated using Newton's second law, F=ma, where F is the force, m is the mass of the plate, and a is the acceleration. The force can also be measured using a force sensor or by using known values for the mass and acceleration. It is important to note that the force may vary at different points on the plate, so multiple measurements may be necessary.

Similar threads

Replies
5
Views
2K
Replies
31
Views
3K
Replies
3
Views
3K
Replies
5
Views
2K
Replies
7
Views
2K
Replies
1
Views
1K
Replies
4
Views
4K
Back
Top