- #246
JesseM
Science Advisor
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Yes, this has always been obvious to me, but I don't see the relevance.neopolitan said:I'm glad that you point out that EB is causally linked to EA. I thought you had grasped that (perhaps not consciously) the whole time.
It's certainly invariant in B's frame, but if you think it's "Lorentz invariant" you misunderstand the meaning of the term. "Lorentz invariant" means "invariant under the Lorentz transform", i.e. something which is the same in all inertial frames, like the invariant interval ds^2 = dx^2 - c^2*dt^2. The distance between B and the location of EA is not something that's the same in every frame (in fact in most frames it's not constant with time), so it's not Lorentz invariant.neopolitan said:Think like this, if you can. According B, B is stationary, so the distance between B and the location of EA never changes, correct? So the distance between B and the location of EA at any time, according to B, is invariant (Lorentz invariant but B doesn't need to say that).
Sure.neopolitan said:When A and B are colocated, tB = 0 and 4 time units later B passes a photon, so B "knows" that the separation between B and the photon when A and B were colocated was 4 space units. Correct?
I'm not sure how you think this is relevant. Yes, obviously EA, EB, the event of the photon passing B, and the event of the photon passing A all lie on the worldline of a single photon. This doesn't change the fact that x'A is defined as the difference in position between the first and third event in the A frame, while xB is defined as the difference in position between the second and fourth event in the B frame, and that your derivation assumes all four events have a light-like separation from one another. So your equation x'A = gamma*(xB - vtB) does not have the same physical meaning as the Lorentz equation x' = gamma*(x - vt) despite the fact that it looks similar, because in the Lorentz equation x' and x either represent the coordinates of a single event in the primed and unprimed frame (which can be at any arbitrary position, not necessarily on one of the frame's spatial axes), or else x' and x can represent the coordinate intervals in two frames between a single pair of events (which can also be located at arbitrary positions, and which need not have a light-like separation from one another).neopolitan said:If the photon was spawned by EA it will pass EB, so a photon spawned by EA is indistinguishable from a photon spawned by B. Correct?
My equations reflect this. How I can word that so that it makes you happy, I don't know.
But they're not indistinguishable, not when you keep in mind the physical meaning of the terms in your equations vs. the physical meaning of the terms in the Lorentz transformation.neopolitan said:What I do know is that somehow I have single handedly come up with a way to derive equations which are indistinguishable from the Lorentz transformations.
Not if you explained the physical meaning of the terms. I'm going to try to draw some diagrams of my own to show the difference in the meaning of the terms visually.neopolitan said:Not sure what I should call them though, since if I tell people I have derived these new equations, they will tell me "No, that is just a recasting of the Lorentz transformations". I'm pretty damn sure that if I started off like that, saying I had new equations which just look like Lorentz transformations, you would be telling me that they are not new, they actually are the Lorentz transformations recast.
Yes, new equations which are only applicable to the very specific definitions of the events you've given (all lying on the path of a single light ray, all lying on either the space or the time axis of one of the two frames), as opposed to the Lorentz transformation which can apply to any arbitrary event or pair of events.neopolitan said:But that's ok, I've come up with new equations. I'm happy with that.